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3 years ago

When rolling a 12-sided number cube, find the probability of Rolling a 12.

Mathematics

1 answer:

Artemon [7]3 years ago

4 0

Answer:

umm...1/12 of a chance

Step-by-step explanation:

Are you sure there isnt a graph that goes along with this?

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Please answer quick! I've been stuck on this one a bit, I keep getting the wrong answer. (I'm not the best at math so maybe ya'l

g100num [7]

Answer:

x= 5.6

Step-by-step explanation:

Basically, if you do 7÷5 it would equal 1.4 so you would have to multiply 4x1.4 which would equal 5.6.

In conclusion 4/7 = 5.6/5

8 0

3 years ago

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Evaluate. −27/125−−−−√3 A.-9/25 B.-3/5 C.9/25 D.3/5

Vladimir79 [104]

$\sqrt[3]{\dfrac{-27}{125}} = -\sqrt[3]{\left(\dfrac{3}{5}\right)^{3}}=\dfrac{-3}{5}$

The appropriate choice appears to be ...
B. -3/5

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3 years ago

Read 2 more answers

What is meant by the term total installment price?

alex41 [277]

Answer:

COMPOUND PROBABILITY: John has a cookie jar with the following cookies in it. He plans to eat 2 cookes. What is the probability that he will select a Macadamia Nut Cookie AND then select a Cranberry Pecan cookie? Remember, since he is eating the cookies, he will not be replacing the cookies in the jar and the order he selects the cookies does not matter here. Simply all answers to lowest terms

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3 years ago

Salía works for Pizza Hut. She earns $9 per hour and $5 for every delivery she makes. She wants to earn more than $150 in an 8-h

Leokris [45]

16 because if she wants to do it in a 8 hour work day she’d make $72 and make 16 deliveries and have two extra dollars

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3 years ago

Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .

Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of $F$ around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

$F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle$

Therefore,

$P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y$

Let's calculate the needed partial derivatives.

$P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0$

Thus,

$Q_x -P_y = 0 -2 = - 2$

Now, by the Green's theorem, we have

$\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x \Big|_{-3}^{4} = -42$

4 0

3 years ago