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3 years ago

Which expression is equivalent to y^4? A. 4•y B. y•y^3 C. 3y+y D. y^2+y^2

Mathematics

2 answers:

Sladkaya [172]3 years ago

5 0

The answer is B !!! =y^4

katrin [286]3 years ago

3 0

Answer:

B: y * $y^{3}$

Step-by-step explanation:

$y^{4}$ = y*y*y*y

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Harold bought 5 apples for $ 1.30. What is the unit price?

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What is unit price?- unit price is the cost of one item(which in this case is an apple)

5 apples- $1.30
1 apple- 1.30 / 5
= $0.26

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Step-by-step explanation:

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3 years ago

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Recall that in the problem involving compound interest, the balance A for P dollars invested at rate r for t years compounded n

RoseWind [281]

Answer:

(a)∴A=$6753.71.

(b)∴A=$1480.24

(c) ∴P=$7424.70

(d)∴P=$49759.62

(e)∴P=$5040.99

(f) ∴P=$2496.11

Step-by-step explanation:

We use the following formula

$A=P(1+\frac rn)^{nt}$

A=amount in dollar

P=principal

r=rate of interest

(a)

P=$2,500, r=5%=0.05,t =20 years , n= 4

$A=\$2500(1+\frac{0.05}{4})^{(20\times 4)$

=$6753.71

∴A=$6753.71.

(b)

P=$1,000, r=8% =0.08,t =5 years , n= 2

$A=\$1000(1+\frac{0.08}{2})^{(5\times 2)$

=$1480.24

∴A=$1480.24

(c)

A=$10,000, r=6% =0.06,t =5 years , n= 4

$10000=P(1+\frac{0.06}{4})^{(5\times 4)}$

$\Rightarrow P=\frac{10000}{(1+0.015)^{20}}$

$\Rightarrow P=7424.70$

∴P=$7424.70

(d)

A=$100,000, r=6% =0.06,t =10 years , n= 12

$100000=P(1+\frac{0.07}{12})^{(10\times 12)}$

$\Rightarrow P=\frac{100000}{(1+\frac{0.07}{12})^{120}}$

$\Rightarrow P=49759.62$

∴P=$49759.62

(e)

A=$100,000, r=10% =0.10,t =30 years , n= 12

$100000=P(1+\frac{0.10}{12})^{(30\times 12)}$

$\Rightarrow P=\frac{100000}{(1+\frac{0.10}{12})^{360}}$

$\Rightarrow P=5040.99$

∴P=$5040.99

(f)

A=$100,000, r=7% =0.07,t =20 years , n= 4

$100000=P(1+\frac{0.07}{4})^{(20\times 4)}$

$\Rightarrow P=\frac{100000}{(1+\frac{0.07}{4})^{80}}$

$\Rightarrow P=2496.11$

∴P=$2496.11

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3 years ago

Which expression has a value of 20?

Mice21 [21]

Answer:

the fist one is equal to 20

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Verdich [7]

Answer:

6x ≥ 3 + 4(2x - 1)

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⇔ 6x - 8x ≥ 3 - 4

⇔ -2x ≥ -1

⇔ 2x ≤ 1 (or 1 ≥ 2x)

⇔ x ≤ 1/2

⇔ x ≤ 0.5

The answer for the question should be:

1 ≥ 2x

6x ≥ 3 + 8x – 4

and the first graph.

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