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2 years ago

I don't remember how to solve this problem I missed yesterday when we learned it. 4(x-2+y)

Mathematics

1 answer:

kow [346]2 years ago

3 0

Answer:

4x - 8 + 4y

Step-by-step explanation:

4(x - 2 + y)

4x - 8 + 4y

You multiply each term in the parenthesis by the number in front of it.

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The smallest angle in a triangle measures 9 degrees less than the middle angle. The largest angle is 26 degrees more than 3 time

xeze [42]

Answer:

Step-by-step explanation:

A+B+C = 180°

A ≤ B ≤ C

B = A+9

C = 3A+26

A+B+C = A + (A+9) + (3A+26) = 5A + 35° = 180°

5A = 145°

A = 29°

B = A+9 = 38°

C = 3A+26 = 113°

6 0

2 years ago

I need help you solve this by using elimination and substitution thank you

AnnZ [28]

Answer: Just use MathPapa.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Can someone please help me with my Question #29 of The Quadratic Relations for me please?

lara [203]

Answer:

Calculate the first differences between the y-values:

$\sf 3 \underset{+1}{\longrightarrow} 4 \underset{+3}{\longrightarrow} 7 \underset{+5}{\longrightarrow} 12 \underset{+7}{\longrightarrow} 19$

As the first differences are not the same, we need to calculate the second differences:

$\sf 1 \underset{+2}{\longrightarrow} 3 \underset{+2}{\longrightarrow} 5 \underset{+2}{\longrightarrow} 7$

As the second differences are the same, the relationship between the variable is quadratic and will contain an $x^2$ term.

--------------------------------------------------------------------------------------------------

To determine the quadratic equation

The coefficient of $x^2$ is always half of the second difference.

As the second difference is 2, and half of 2 is 1, the coefficient of $x^2$ is 1.

The standard form of a quadratic equation is: $y=ax^2+bx+c$

(where a, b and c are constants to be found).

We have already determined that the coefficient of $x^2$ is 1.

Therefore, a = 1

From the given table, when $x=0$ , $y=12$ .

$\implies a(0)^2+b(0)+c=12$

$\implies c=12$

Finally, to find b, substitute the found values of a and c into the equation, then substitute one of the ordered pairs from the given table:

$\begin{aligned}\implies x^2+bx+12 & = y\\ \textsf{at }(1,19) \implies (1)^2+b(1)+12 & = 19\\ 1+b+12 & = 19\\b+13 & =19\\b&=6\end{aligned}$

Therefore, the quadratic equation for the given ordered pairs is:

$y=x^2+6x+12$

7 0

2 years ago

What is a prime number

Vitek1552 [10]

Answer:

3,5,7,11

Step-by-step explanation:

Prime numbers are special numbers that can only be divided by themselves and 1.

4 0

3 years ago

Write the arithmetic series using summation notation. 7.5+13.5+19.5+25.5+31.5+37.5

Pavlova-9 [17]

Answer:

135

Step-by-step explanation:

its easier to take out the decimal first then add the rest then add the decimals together then add the two numbers to get the final answer

6 0

3 years ago