Three students want to estimate the mean backpack weight of their schoolmates. To do this, they each randomly chose 8 schoolmates and weighed their backpacks. Then as per the given sample data,
(a) The sample means of the backpacks are: 6.375,6.375,6.625
(b) Range of sample means: 0.25
(c)The true statement is: The closer the range of the sample means is to 0, the less confident they can be in their estimate.
For the first sample, mean= 6.375
For the second sample, mean= 6.375
For the third sample, mean= 6.625
Range of sample means=Maximum Mean- Minimum Mean
= 6.625 - 6.375
= 0.25
The students will estimate the average backpack weight of their classmates using sample means, the true statement is:
The closer the range of the sample means is to 0, the more confident they can be in their estimate.
Learn more about range here:
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Dawson's annual premium will be $2,462.40. This can be found by going across from "Male 40-44" over to "20-year coverage" which is $13.68. Since $13.68 is per $1000 of coverage, you would multiply it by 180 to get $2,462.40.
Rachel's checks I believe would have a deduction of $63.14.
I believe it is positive so option 2
Answer:
The condition for r is the following:
And for this case if we analyze the options the only impossible value is given by:
1.0528
Because this value is higher than 1 and not satisfy the general limits for r
Step-by-step explanation:
The correlation coefficient is a measure of dispersion and is a value between -1 and 1, and is defined as:
![r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bn%28%5Csum%20xy%29-%28%5Csum%20x%29%28%5Csum%20y%29%7D%7B%5Csqrt%7B%5Bn%5Csum%20x%5E2%20-%28%5Csum%20x%29%5E2%5D%5Bn%5Csum%20y%5E2%20-%28%5Csum%20y%29%5E2%5D%7D%7D)
The condition for r is the following:
And for this case if we analyze the options the only impossible value is given by:
1.0528
Because this value is higher than 1 and not satisfy the general limits for r
