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motikmotik
3 years ago
10

Find the height of a cylinder with a surface area of 1,206.4 in^2 and a radius of 8 in.

Mathematics
2 answers:
fgiga [73]3 years ago
8 0

Answer:

h = 16 inches

Step-by-step explanation:

The surface area of a cylinder is given by

SA = 2 pi r^2 + 2 pi rh

We know the surface area and the radius

1206.4 = 2 ( 3.14) * 8^2 + 2 * 3.14 * 8 *h

1206.4 = 401.92+50.24h

Subtract 401.92 from each side

1206.4-401.92 = 401.92-401.92+50.24h

804.48=50.24h

Divide each side by 50.24

804.48/50.24 =50.24h/50.24

16.01273885=h

dolphi86 [110]3 years ago
4 0

Answer:

h=16.01 inch

Step-by-step explanation:

Surface area of the cylinder=1206.4 inch^2

Radius of the cylinder=8 inch

Surface area of a cylinder= (2*\pi *r*h)+(2*\pi *r^2)

As, \pi =\frac{22}{7} =3.14

1206.4=(2*3.14*8*h)+2*3.14*8*8\\\\1206.4=(2*3.14*8*h)+(2*3.14*64)

1206.4=50.24*h+401.92\\\\804.48=50.24*h\\\\h=804.48/50.24\\\\ h=16.01 inch

The height of the cylinder is: h=16.01 inch

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Answer:

\displaystyle -20

Step-by-step explanation:

\displaystyle -9[5] + 3[7] + 4 = -45 + 21 + 4 = -20

I am joyous to assist you anytime.

5 0
3 years ago
I NEED HELP AND IM ON A TIMED TEST
stira [4]

This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

7 0
3 years ago
How to solve it?........................
Feliz [49]
5x+4=114
5x= 110
X=22

114+ 3(22)-24=156
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3 years ago
Using two independent samples, two population means are compared to determine if a difference exists. The population standard de
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Answer:

Hence the degrees of freedom are associated with the critical value is 25.

Step-by-step explanation:

Using two independent samples, two population means are  

compared to determine if a difference exists, the population standard deviation is equal.  

sample size 1 = n_{1}= 15 and sample size 2 = n_{2} = 12  

since, population standard deviations are equal, required degrees of freedom              

= n_{1}  + n_{2} - 2 \\= 15 + 12 - 2\\ = 25  

8 0
2 years ago
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Arlecino [84]

Answer:

I am so sorry

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I dont really know what it is but I think it is 21.98 you do 7 times 3.14

5 0
3 years ago
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