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2 years ago

9

Mitzi has 79 coins she divides the coins equally among herself and her 3 brothers Mitzi will keep any coins left over how many c

oins does each person get

1 answer:

Elanso [62]2 years ago

7 0

Answer:

19

Step-by-step explanation:

79÷4=19R3

≈ 19

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SOMEONE PLEASE HELP ME ASAP PLEASE!!!

aniked [119]

Answer:

2, 1

Step-by-step explanation:

In the sequence, each number is half of the previous number.

So we would multiply by 1/2 or divide by 2 to find the next number.

We can test this with a few numbers:

64*1/2=32

16*1/2=8

So the first missing number is 1/2 of 4.

1/2*4=2

The second missing number is 1/2 of the first missing number.

1/2*2=1

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3 years ago

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What is the best estimate for the height of a desk 1 m 1 km

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1m is approximately 3 feet whereas 1m is approximately 3280 feet. Therefore, the best estimate for the heiht of a desk would be 1 m

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3 years ago

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The line below has slope 4 and y-intercep

romanna [79]

Answer:

y=4x+3

y=-2x+3

Step-by-step explanation:

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2 years ago

In recent years, only 79% of the fruit sold at Fred's Fruit stand has been any good. Fred recently started buying fruit from new

Juli2301 [7.4K]

Answer:

The p-value of the test is 0.0485 < 0.05, also less than 0.07, so there is sufficient evidence to conclude that there is a statistically significant increase in the percentage of good fruit, for both significance levels, thus the change in significance levels do not change the conclusion.

Step-by-step explanation:

79% of the fruit sold at Fred's Fruit stand has been any good. Test if there has been an increase.

At the null hypothesis, we test if there has been no increase, that is, the proportion is still of 79%, so:

$H_0: p = 0.79$

At the alternative hypothesis, we test if there has been an increase, that is, more than 79% being good, so:

$H_1: p > 0.79$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.79 is tested at the null hypothesis:

This means that $\mu = 0.79, \sigma = \sqrt{0.79*0.21}$

In a random sample if 475 pieces, 85 were bad.

So 475 - 85 = 390 were good, and:

$n = 475, X = \frac{390}{475} = 0.8211$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.8211 - 0.79}{\frac{\sqrt{0.79*0.21}}{\sqrt{475}}}$

$z = 1.66$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion above 0.8211, which is 1 subtracted by the p-value of Z = 1.66.

Looking at the z-table, z = 1.66 has a p-value of 0.9515.

1 - 0.9515 = 0.0485

The p-value of the test is 0.0485 < 0.05, also less than 0.07, so there is sufficient evidence to conclude that there is a statistically significant increase in the percentage of good fruit, for both significance levels, thus the change in significance levels do not change the conclusion.

5 0

3 years ago

Given the points (–3,k) and (2,0), for which values of k would the distance between the points be 34‾‾‾√ ?

galina1969 [7]

The distance between the points (–3,k) and (2, 0) exists k = ± 3.

How to estimate the distance between points (–3, k) and (2, 0)?

To calculate the distance between two points exists equal to

$d=\sqrt{(y 2-y 1)^{2}+(x 2-x 1)^{2}}$

we have (-3, k) and (2, 0)

$$&d=\sqrt{34}$

substitute, the values in the above equation, and we get

$$\sqrt{34} &=\sqrt{(0-k)^{2}+(2+3)^{2}} \\$

simplifying the above equation

$$\sqrt{34} &=\sqrt{(-k)^{2}+(5)^{2}} \\$

$$\sqrt{34} &=\sqrt{k^{2}+25}$

squared both sides

$$&34=k^{2}+25 \\$

$$&k^{2}=34-25 \\$

$$&k^{2}=9 \\$

k = ± 3

Therefore, the value of k = ± 3.

To learn more about distance refer to:

brainly.com/question/23848540

#SPJ4

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1 year ago