Answer:
The answer to your question is the first choice
Step-by-step explanation:
Data
Force = 465 N
bearing = 19°
Process
1.- Find the components using trigonometric functions
To find the horizontal component use cosine
To find the vertical component use sine
cos Ф = x/F sin Ф = y/F
Substitution
cos 19 = x/465 sin 19 = y/465
x = 465 cos 19 y = 465 sin 19
x = 439 N y = 151.39 N
2.- Rounding to the nearest number
Horizontal component = 440N
Vertical component = 151 N
Answer:
a^2+b^2=c^2
Step-by-step explanation:
a, b, c each represent a side. Lets say a triangle has a=2 and b=4.
- a^2= 2^2= 2*2= 4 do the same with B.
b^2= 4^2= 4*4= 16
2. a^2+ b^2= 4+16= 20= c^2
<u><em>Get it?</em></u>
Answer:
that number is 100
Step-by-step explanation:
Firstly, we will find place value of 9 in 392,065.018
3<u>9</u>2,065.018
We can see that
it is at 10th thousand place
so, place value of 9 is
now, we are given
a number in which the value of 9 is 1/100 the value of the 9 in the number 392,065.018
so, we can get a number as
now, we can simplify it
So, that number is 100
Answer:
Step-by-step explanation: Need to work out your scale factor which is 1.5.
8 * 1.5 = 12
CE = 12
12 * 9 = 108/2 = 59 that is the area of triangle ACE
8 * 6 = 48/2 = 24 that is the area of triangle BCD
ACE - BCD = ABDE
59 - 24 = 35cm^2
Answer:
Step-by-step explanation:
Our inequality is |125-u| ≤ 30. Let's separate this into two. Assuming that (125-u) is positive, we have 125-u ≤ 30, and if we assume that it's negative, we'd have -(125-u)≤30, or u-125≤30.
Therefore, we now have two inequalities to solve for:
125-u ≤ 30
u-125≤30
For the first one, we can subtract 125 and add u to both sides, resulting in
0 ≤ u-95, or 95≤u. Therefore, that is our first inequality.
The second one can be figured out by adding 125 to both sides, so u ≤ 155.
Remember that we took these two inequalities from an absolute value -- as a result, they BOTH must be true in order for the original inequality to be true. Therefore,
u ≥ 95
and
u ≤ 155
combine to be
95 ≤ u ≤ 155, or the 4th option