The box has volume
11 in × 3 in × <em>x</em> in = 33<em>x</em> in³
and surface area
2 (11 in × 3 in + 11 in × <em>x</em> in + 3 in × <em>x</em> in) = (66 + 28<em>x</em>) in²
The volume and area have the same value if
33<em>x</em> = 66 + 28<em>x</em>
Solve this equation for <em>x</em> :
33<em>x</em> - 28<em>x</em> = 66
5<em>x</em> = 66
<em>x</em> = 66/5 = 13.2
Step-by-step explanation:
f(g(10))
This is called a composite function. It's when you plug one function into another.
First, find g(10):
g(x) = √(x-9)
g(10) = √(10-9)
g(10) = √1
g(10) = 1
Then plug that into f(x):
f(x) = -9x - 9
f(g(10)) = -9 g(10) - 9
f(g(10)) = -9 (1) - 9
f(g(10)) = -9 - 9
f(g(10)) = -18
Answer:
B and C
Step-by-step explanation:
Required
Select graphs that are dilated by a scale factor greater than 1
For graph A:
Graph A is smaller than the original graph. This indicates dilation with a scale factor less than 1
For graph B:
Graph B is bigger than the original graph and is dilated over (0,0). This indicates dilation with a scale factor greater than 1
For graph C:
Graph C is bigger than the original graph; however, it is not dilated over (0,0). This indicates dilation with a scale factor greater than 1
For graph D:
Graph D is bigger than the original graph; however, it is not only dilated but also flipped over (i.e. rotated).
<em>Hence, b and c is true</em>
Answer:
90
Step-by-step explanation:
