Equation: (70 + 70*.05) + (580 + 580*.07) + (620 + 620*.10) = Total Spent
Solving for this gets you $1320.30.
Step-by-step explanation: look so if you have
shcool A its 8v+4b=12
and
School B: 12v+4b= 16
since both classes used 4 busses we can use elimination by subtracting the A class Equation from the b class equation to solve from v for its value Then, use either equation and the now found value for v to solve for b.
You should find part of the process to be
12v+4b-(8v+4b)=12-16 which shows the van holds only a few people even before continuing the solution.
Answer -4
Answer:
Tommy had 56 cents in start and Loren had 7 cents in start.
Step-by-step explanation:
Let,
x be the money Tommy have.
y be the money Loren have.
According to given statement;
Tommy had 8 times more money than Loren.
x = 8y Eqn 1
Parents gave 35 cents to Loren and Tommy spent 14 cents, therefore
x-14=y+35 Eqn 2
Putting x=8y in Eqn 2
Dividing both sides by 7
Putting y=7 in Eqn 1
Hence,
Tommy had 56 cents in start and Loren had 7 cents in start.
Let number of fives = x then number of ones = 3x and number of tens = x - 1
so we can create the equation
x + 3x + x-1 + y = 26 where y = number of twenties
so
5x + y = 27
also we have the equation
5x + 3x + 10(x - 1) + 20y = 120
18x + 20y = 130..................................(1)
5x + y = 27 multiply by -20:-
-100x - 20y = -540..............................(2)
Adding equation (1) and (2)
-82x = -410
x = 5, that is 5 fives
Now plug x = 5 into equation 1:-
18(5) + 20y = 130
20y = 40
y = 2 , that is 2 twenties
So the answer is there are (3x) = 15 ones , 5 fives, 4 tens and 2 twenties
