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3 years ago

Question 4 of 5

Mathematics

2 answers:

sergejj [24]3 years ago

6 0

Answer:

C. A'(-5-5), B'(-1,-5), C (-1.-2) D'(-5-1)

Step-by-step explanation:

Your welcome

grigory [225]3 years ago

3 0

It will definitely be C

any time there it a reflection across the x-axis the coordinates then become (x,-y)

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A newly opened juice shop earned a profit of $2,400 in the first month. For the remaining months of the year, the expected profi

atroni [7]

First month's profit of the company = $2,400.

After the first month, the profit is modeled by the function

J(t) = 2.5t + 1,250, t is the number of months after the first month the shop opened.

Now, P(t) describes the total profit earned by the company.

So, P(t) = (Profit earned from first month) + (Profit earned from remaining 11 months of the year)

= 2400 + (2.5t + 1250)

Hence, total profit earned for the year = 2.5t + 3650.

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2 years ago

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and me

Dovator [93]

Answer:

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

$e = 2.71828$ is the Euler number

$\mu$ is the mean in the given time interval.

The problem states that:

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.

To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.

There are 5 weekdays, with a mean of 0.1 calls per day.

The weekend is 2 days long, with a mean of 0.2 calls per day.

So:

$\mu = \frac{5(0.1) + 2(0.2)}{7} = 0.1286$

If today is Monday, what is the probability that Ben receives a total of 2 phone calls in a week?

This is $P(X = 2)$ . So:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-0.1286}*0.1286^{2}}{(2)!} = 0.0073$

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

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2 years ago

Which of the following graphs represents a function?

4vir4ik [10]

Answer: you didnt post graphs to look at

Step-by-step explanation:

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3 years ago

Read 2 more answers

From the moment the first car started how many hours will it take the second car to catch up to the first

Rina8888 [55]

Answer:

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Step-by-step explanation:

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3 years ago

Solve the equation f/6= 2.5

dezoksy [38]

Answer:

f=15

Step-by-step explanation:

f/6=2.5

f=2.5*6

f=15

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3 years ago