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koban [17]
3 years ago
12

A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1, −7).

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
4 0

Therefore, the required vertices after rotation are W'(5,3), X'(3,1),Y'(5,-1) and Z'(7,1).

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C= 6x+100 and c=10x+80 <br> what number does x have to be for c to be the same on each equation?
slega [8]

Answer:

x= 5 , for c to be same on each eqn

7 0
1 year ago
The function f(x)=125(0.9)x models the population of a species of fly in millions after x years.
SSSSS [86.1K]
A word to the wise:  It's  <span> f(x)=125(0.9)^x,   where ^ represents exponentiation.

In this case the ave. value over the interval [11, 15] is

 125(0.9)^15 - 125(0.9)^11
------------------------------------- = (125/4) [ 0.9^15 - 0.9^11)
               15 - 11                    =  (31.25) [ 0.2059 - 0.3138 ] = a negative result
                                              =  (31.25)(-0.1079) = -3.372  (av. r. of c.
                                                     over the interval [11,15] )

Do the same thing for the time interval [1,5].  Then compare the two rates of change.</span>
6 0
2 years ago
Read 2 more answers
[IMAGE] please help me with 1, 2, and 3
LUCKY_DIMON [66]

Answer:

1. 5n + 10d = 90

2. (18,0)

3. (0,9)

7 0
2 years ago
Parallel to 7x+5y=3, through (9,-9)
love history [14]
The answer should be -5x + 7y = -108

3 0
2 years ago
20 points!!! first answer gets brainliast. Don't need too much explanation thank you!​
KengaRu [80]

Answer:

The answer to your question is below

Step-by-step explanation:

2. \sqrt{-128}                Just find the prime factors of 128 and simplify

   \sqrt{-2^{7}} = \sqrt{-2^{6} 2} = 2^{3}i \sqrt{2}

   8i\sqrt{2}

3.- \sqrt{-9} + \sqrt{-16}     Get the square roots and simplify

     3i + 4i

     7i

4.- None of the choices is equal to one, because the exponents are pair.

5.- 1/3x² + 10 = 7

    1/3x² = 7 - 10

    1/3x² = -3

         x² = -3(3)

         x² = -9

         x = ±3i

8 0
3 years ago
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