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koban [17]
3 years ago
12

A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1, −7).

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
4 0

Therefore, the required vertices after rotation are W'(5,3), X'(3,1),Y'(5,-1) and Z'(7,1).

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21) Find x. Show your work.
shepuryov [24]

Answer:

x = 21

Step-by-step explanation:

Givens:

Every triangle's interior angles add up to 180°

The triangle has a right angle.

The triangle is isosceles (two equal sides and two equal angles)

Let's make an equation with the information we have already.

2 × (2x + 3) + 90 = 180

4x + 6 + 90         = 180

4x + 96                = 180

4x                         = 84

x                           = 21

4 0
3 years ago
Please help me find the area of the trapezoid
alex41 [277]
Formulas:
A= (b1+b2) /2 X h

A= (22.2+8.52) x 9.86
A=30.72x9.86
A= 302.90
5 0
3 years ago
Read 2 more answers
If you have time help, please!
Viefleur [7K]

Answer:

The point on the y-axis is (0,-3) and the point on the x-axis is (6,0)

Step-by-step explanation:

Start by plotting -3 on the y-axis

Then move up 1 and over 2 from there

7 0
3 years ago
While shopping for clothes Tracy spent $38 less than three times what Daniel spent right and solve an equation to find how much
Gnom [1K]

Answer:

y=3x-38

Step-by-step explanation:

We know that Tracy spent $38 in less than 3 times than what Daniel spent. Given this information we can put our eqaution together.

Y=3x-38

Hope this helps! :)

6 0
3 years ago
Kind people!help me please...And a detailed solution/THANKS<br> sin^2x-0,5sin2x=0
Volgvan

This will be easier to write, and a lot easier to read, if we temporarily
use another symbol ... say, 'Q' ... to represent  ' sin(2x) ' .
Here we go:

Original equation:                Q² - 0.5 Q  =  0

Factor the left side:            Q (Q - 0.5)  =  0

This equation is true if either factor is zero:


--  If  Q=0, then  sin(2x) = 0

                                 2x = 0°,  180°,  360°

                                   x = 0°,  90°,  180°


-- If  (Q-0.5) = 0, then      Q  =  0.5

                                sin(2x)  =  0.5          

                                       2x  =  30°,  150°

                                         x  =  15°,  75°


The whole collection of solutions
between  0°  and  360° :

          x = 0°,  15°,  75°,  90°,  180° .

8 0
3 years ago
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