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3 years ago

Could someone please help answer this, Thanks so much, please no spam, will give brainliest (homework help)

Mathematics

1 answer:

Elza [17]3 years ago

7 0

Answer:

b<-7

Step-by-step explanation:

3b+3<-18

subtract 3 on both sides

3b<-21

divide 3 on both sides

b<-7

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A walking path across a park is represented by the equation y = -3x - 6. A

Brrunno [24]

I think y=-3x - 6 is right

5 0

3 years ago

Please answer correctly, will give brainly to best answer, please do explain your answer

Liono4ka [1.6K]

Answer: 26

2³ + 4(2 + x) for x = 10

- first do 4(2 + x) which is

8+4x

- Evaluate 2 cubed

You get 2 times 2 times 2.

That would get 8

Our expression is 8 + 8+x

x = 10

Substitute the values.

It is Now eight plus 8 plus ten

So when you Calculate eight plus 8 plus 10

You will get 26

6 0

3 years ago

Read 2 more answers

Simplify each expression. Assume that all variables are positive.

kozerog [31]

Q1. The answer is $\frac{8x^{3}y^{6} }{27}$

$( \frac{16 x^{5} y^{10}}{81x y^{2} } )^{ \frac{3}{4} }= ( \frac{16}{81}* \frac{ x^{5} }{x}* \frac{ y^{10} }{y^{2}} )^{ \frac{3}{4} } \\ \\ 
 \frac{ x^{a} }{ x^{b} }= x^{a-b} \\ \\ 
( \frac{16}{81}* \frac{ x^{5} }{x}*\frac{ y^{10} }{y^{2}} )^{ \frac{3}{4} }}=( \frac{16}{81 }* x^{5-1}* y^{10-2})^{ \frac{3}{4} }=( \frac{16}{81 }* x^{4}* y^{8})^{ \frac{3}{4} }= \\ \\ = (\frac{16}{18} )^{ \frac{3}{4} }*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=$
$\frac{(16)^{ \frac{3}{4} }}{(18)^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } \\ \\ 
 (x^{a} )^{b} = x^{a*b} \\ \\ 
\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } = \frac{ 2^{4* \frac{3}{4} } }{ 3^{4* \frac{3}{4} } } * x^{4* \frac{3}{4} } * y^{8*\frac{3}{4}} = \frac{ 2^{3} }{ 3^{3} } * x^{3} *y^{6} =$
$= \frac{8x^{3}y^{6} }{27}$

Q2. The answer is 1/16

$(-64) ^ \frac{-2}{3} =(-1* 2^{6} ) ^ \frac{-2}{3}=(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} \\\\x^{-a} = \frac{1}{ x^{a} } \\\\(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} = \frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{(2^{6})^ \frac{2}{3}} \\ \\ (x^{a} )^{b}=x^{a*b} \\\\x^{ \frac{a}{b} = \sqrt[b]{ x^{a} } } \\ \\ 
$
$\frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{2^{6*\frac{2}{3}}} = \frac{1}{ \sqrt[3]{(-1)^{2} } } * \frac{1}{ 2^{4} } = \frac{1}{ \sqrt[3]{1} } * \frac{1}{16} = \frac{1}{1} * \frac{1}{16}= \frac{1}{16}$

Q3. The answer is $a^{ \frac{7}{6} }$

$a^{ \frac{2}{3} } * a^{ \frac{1}{2} } \\ \\ 
 x^{a}* x^{b} =x^{a+b} \\ \\ 
a^{ \frac{2}{3} } * a^{ \frac{1}{2} }= a^{ \frac{2}{3} + \frac{1}{2} } =a^{ \frac{2*2}{3*2} + \frac{1*3}{2*3} }=a^{ \frac{4}{6} + \frac{3}{6} }=a^{ \frac{4+3}{6} }=a^{ \frac{7}{6} }$

7 0

3 years ago

Find x<br> A)-2<br> B)5<br> C)-5<br> D)9

Arte-miy333 [17]

Answer:

Step-by-step explanation:

From the figure, we can say:

∠NFG + ∠EFN = ∠EFG

We substitute the given measure and write:

6x + 4 + 24 = 12x - 2

Now, we simply solve this algebraically for "x". Shown below:

$6x + 4 + 24 = 12x - 2\\6x+28=12x-2\\28+2=12x-6x\\30=6x\\x=\frac{30}{6}\\x=5$

x is 5, so B is the correct answer.

3 0

3 years ago

What is the lateral and surface area? I will give the brainliest if you answer correctly and no links or you will be reported

jeyben [28]

Answer:

Lateral: 560

Surface Area: $560 + 96\sqrt{3}$

Step-by-step explanation:

Well, we know that the lateral area is just the surface area subtracted by the hexagon base of the figure. Thus, if we (1) find the area of one of the triangular faces and multiply by 6, we get the lateral area. And then, if we (2) add the area of the hexagonal base, we get the surface area.

Let's do (1) first to get the lateral area

They mention that the base of one of the triangular faces is 8 and its height (which is the slant height) is 20. So the area is simply 20 * 8/2 = 80

Then, we multiply by 6 because there are 6 of these triangles and get 560

So the lateral area is 560

Let's do (2) next to find the surface area

If we add the area of the hexagonal base to 560, we obtain the surface area

The hexagon is a regular hexagon with a length of 8. Now, the area of a hexagon $3\sqrt{3} * s^2 /2$ where $s$ is the side. We can obtain this formula if we separate the hexagon into 6 equilateral triangles.

Plugging in 8 for $s$ we get $96\sqrt{3}$

So the surface area is $560 + 96\sqrt{3}$

7 0

3 years ago