Answer: 40,823
Step-by-step explanation:
![x^ \frac{m}{n}= \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7Bm%7D%7Bn%7D%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%20)
pemdas, so exponent first before multiply
4(x^1/2)=4x^2
this is different from
(4x)^1/2
so
![x^ \frac{1}{2}= \sqrt[2]{x^1}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7B1%7D%7B2%7D%3D%20%5Csqrt%5B2%5D%7Bx%5E1%7D%20%20)
times that by 4
4√x
Answer:
3) 5
4) 8.2
5) 6.8
6)FG = 6.4
7) EF = 3.6
8)DF = 4.8
Step-by-step explanation:
From the attached triangle, using trigonometric ratio we can find ∠G as; tan^(-1) (6/8)
Thus, ∠G = 36.87°
Still using trigonometric ratios;
FG/8 = cos 36.87°
FG = 8 cos 36.87°
FG = 6.4
3) EF + FG = EG
Since EG is 10, mean of EF and FG = 10/2 = 5
4) mean of EG and FG = (10 + 6.4)/2 = 8.2
5) EF + FG = EG
Thus; EF = EG - FG
EF = 10 - 6.4
EF = 3.6
Mean of EG and EF = (10 + 3.6)/2 = 6.8
6) FG = 6.4
7) EF = 3.6
8) Using trigonometric ratio;
DF/8 = sin 36.87
DF = 8 × 0.6
DF = 4.8
Answer:
2s or 3s
Step-by-step explanation:
Given the function that models the height of the object as;
h(t) = - 16t^2 + 80t + 96
The ball reaches the ground when h = 0
Substitute
0 = - 16t^2 + 80t + 96
Divide through by -16
0 = t²-5t-6
t²-5t-6 = 0
t²-2t-3t+6 = 0
t(t-2)-3(t-2) = 0
(tt-2)(t-3) = 0
t - 2 = 0 and t-3 = 0
t = 2 and 3s
Hence it will take the ball 2s or 3s to reach the ground
I think the mean would be the best because the data distribution is neither the mean nor median
