The information given is sufficient for this proof .
Slope of a line passing through x1 ,y1) and ( x2,y2) is given by the formula :
M = ( y2 - y1)/ ( x2-x1)
________________________________
Let us start finding the slope of line PQ
the given points are ( a,b) and ( c,d)
using the slope formula we get :
slope of line PQ = m= ( d-b) /( c-a)
Let us now try finidng slope of the another line P'Q'
It is passing through ( -b ,a) and (-d,c)
using the formula we get slope of P'Q' = m' = ( c-a) /( -d - -b)
m'= ( c-a) /( -d+b)
m'= ( c-a) / -( b-d Let us find the product of m and m' :
( d-b ) * ( c-a)
----------- ------------ = -1
(c-a) - ( b-d)
Because we got product of m and m' = -1 hence proved product of perpendicular lines are negative reciprocal of each other .
Y+ 3/4 = 6
⇒ y= 6 - 3/4
⇒ y= 24/4 - 3/4
⇒ y= 21/4
⇒ y= 5 1/4
The correct answer is y= 5 1/4~
The residual value is -1.14.
Plug 5 into x
y=-0.7(5)+2.36
=-1.14
The answer would be B if I’m not wrong
this means 2 x 2 x 2 x 2 x 2
so you put 2 on the bottom and a small 5 in the top right of it to show that you are multiplying the 2, 5 times.<span />