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marshall27 [118]
3 years ago
6

Identify an equation in slope intercept form for the line parallel to Y equals 4X -9 that passes through (-5,3)

Mathematics
1 answer:
Kobotan [32]3 years ago
7 0

Slope intercept form of a line is y=mx+b where m= slope and b=y-intercept.

Now compare this form with the tiven equation y=4x-9 to get the value of m.

So, m= 4.

Slope of all parallel lines are always equal. Which means the line which is parallel to this has also the same slope: m=4.

Now we need to find the value of b to get the equation. That parallel line passes through (-5,3).

The point intercept form of a line is,

(y-y1)=m(x-x1)

So, we can plug in the m=4, x1=-5 and y1=3 in the above equation. Hence,

y-3=4(x-(-5))

y-3=4(x+5) Since -(-5)=+5

y-3=4x+20 By distributing property.

y=4x+20+3 Adding 3 to each sides.

y=4x+23

So, the slope-intercept form of that parallel line is y=4x+23.

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Write .27 as a fraction in simplest form.
Debora [2.8K]

Answer:

27/100

Step-by-step explanation:

It's in the hundreths,

so we just put 27 over 100

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2 years ago
The area of a square is given by x?, where x is the length
Rudik [331]

Answer:

Step-by-step explanation:

If she doubles the area of her lot, it should be 2x^2.

But how do you get that?

The answer is that the sides have now increased to √2x

How did I get that, and why did I choose it?

  • The formula for a square's area is s^2
  • If you want to double the area, it will be 2 s^2.  Now what?
  • Take the square root of 2s^2 which is √(2s^2).
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3 years ago
Find the area of the figure. Round to the nearest hundredth if necessary
ki77a [65]
The area of the figure :)

8 0
3 years ago
Read 2 more answers
Question 8 of 10
Andreyy89

Median and IQR are the most appropriate measures of center and spread for this data set.

<h3>Why are Median and IQR the most appropriate?</h3>

Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:

  • Mean is affected by extreme values
  • Mean is not correct if more outliers are present
  • Mean may not represent the nature of the data whether skewed right or left.

Also, the median as the middle entry is not affected by extreme items or outliers, so the median is better than mean,

Furthermore, for the measure of spread, the IQR is better since extreme items will show higher std deviation and also some outliers mislead.

Therefore, Option B is correct.

Read more about measures of center

brainly.com/question/10610456

#SPJ1

5 0
2 years ago
The owner of the Rancho Grande has 3,060 yd of fencing with which to enclose a rectangular piece of grazing land situated along
Pavel [41]

Answer:

1170450 yd^2

Step-by-step explanation:

The first thing is to calculate the necessary perimeter, which would be like this:

2 * a + b = 3060

if we solve for b, we are left with:

b = 3060-2 * a

Now for the area it would be:

A = a * b = a * (3060-2 * a )

A = 3060 * a -2 * a ^ 2

To maximize the area, we calculate the derivative with respect to "a":

dA / da = d [3060 * a -2 * a ^ 2

]/gives

dA / day = 3060 - 4 * a

If we equal 0:

0 = 3060 - 4 * a

4 * a = 3060

a = 3060/4

a = 765 and d

Therefore b:

b = 3060 - 2 * a = 3060 - 1530 = 1530

A = a * b

A = 765 * 1530

A = 1170450 and d ^ 2

3 0
3 years ago
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