Answer:
no because on is equal to 3 when plugged in and the other is equal to 4 when plugged in.
Step-by-step explanation:

Answer:
the answer would be maybe 20 minutes
To check for continuity at the edges of each piece, you need to consider the limit as
approaches the edges. For example,

has two pieces,
and
, both of which are continuous by themselves on the provided intervals. In order for
to be continuous everywhere, we need to have

By definition of
, we have
, and the limits are


The limits match, so
is continuous.
For the others: Each of the individual pieces of
are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
I can’t answer this with out the distance they jumped.