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OverLord2011 [107]
3 years ago
13

A restaurant offers diet soda and regular soda.In one day they sold 64 sodas.If 28 of the sodas they sold were diet, what is the

ratio of regular sodas sold to diet sodas sold?
Mathematics
1 answer:
german3 years ago
7 0

Answer: The ratio of regular sodas sold to diet sodas sold is 9:7

Step-by-step explanation:

The restaurant offers diet soda and regular soda.

In one day they sold a total of 64 sodas. If 28 of the sodas they sold were diet sodas, the rest would be regular sodas. Therefore, the number of regular sodas sold will be 64 - 28 = 36 regular sodas. The ratio of regular sodas sold to diet sodas sold would be the number of regular sodas sold divided by the number of diet sodas sold. It becomes

36/28 = 18/14 = 9/7

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Which of the following fractions has the same value as the decimal number 0.65?
boyakko [2]

Answer:

13/20

Step-by-step explanation:

To find this, divide 13 by 20 to get .65

Hope this helped!

4 0
3 years ago
A kayaker travels x miles per hour downstream for 4 hours. On the 6-hour return trip, the kayaker travels 2 mile per hour slower
Stolb23 [73]

                              time       *      rate          =       distance

Downstream           4           *       x              =          4(x)

Upstream                6           *     x - 2           =        6(x - 2)

distance downstream = distance upstream:

                              4(x) = 6(x - 2)

                               4x  = 6x - 12

                              -2x  =   -12

                                 x   =    6

Distance Upstream: 4x   = 4(6)   = 24

Distance Upstream: 6(x - 2)  = 6(6 - 2)   = 6(4)   = 24

Total distance traveled is Upstream + Downstream = 24 + 24 = 48

Answer: 48 miles

5 0
3 years ago
Jennifer's Flower Shop sells flowers for $1.35 each. Mary's Flower Shop sells a dozen flowers for $15.96. Who has the best deal?
I am Lyosha [343]

Answer:

Mary has the better deal

Step-by-step explanation:

Jennifer's $1.35 * 12 = $16.20

Mary's 12 flowers = $15.96

7 0
3 years ago
Read 2 more answers
Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.
Andre45 [30]

Answer:

Option d)  5 to the power of negative 5 over 6 is correct.

\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}

Above equation can be written as 5 to the power of negative 5 over 6.

ie, 5^\frac{\bf -5}{\bf 6}

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}

Above equation can be written as 5 to the power of negative 5 over 6.

7 0
3 years ago
Compare |-0.658| and |-0.653|
Andre45 [30]

Answer:

|−0.658| < |−0.653|.

Step-by-step explanation:

4 0
3 years ago
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