3 years ago

Y=1/3mx^3 – (m–1)x^2 + 3(m–2)x +1/3

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

8 0

Answer:

not true

Step-by-step explanation:

i just wants points mate

You might be interested in

How to find the solutions for a quadratic inequality?

viktelen [127]

So if your equation was x squared +2x+1=0 you would do (x+1)(x+1)=0 because 1+1=2(x)
then you do x+1-1=0-1 to check it over

8 0

3 years ago

2 divided by 11 times 9 minus 3 squared

BigorU [14]

Using order of operations, you square the 3 and get 9.
then divide 2 by 11, then multiply that by 9 and subtract 9. your answer is -7.363636364

6 0

3 years ago

Question 23(Multiple Choice Worth 1 points) (05.05 MC) Find the area of a triangle with a base length of 4 units and a height of

Ymorist [56]

20 area is width (base) times heighth

3 0

2 years ago

Find the magnitude of WX for W(-2, 8, -3) and X(1, 4, -1)

zheka24 [161]

The magnitude of WX is $\sqrt{29}$ ⇒ c

Step-by-step explanation:

The magnitude of XY (its length) where,

$X=(x_{1},y_{1},z_{1})$
$Y=(x_{2},y_{2},z_{2})$

is IXYI = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}+(z_{2}-z_{1})^{2}}$

∵ W = (-2 , 8 , -3)

∵ X = (1 , 4 , -1)

- To find the magnitude of WX use the formula above

∴ $x_{1}$ = -2 and $x_{2}$ = 1

∴ $y_{1}$ = 8 and $y_{2}$ = 4

∴ $z_{1}$ = -3 and $z_{2]$ = -1

- Substitute these values in the rule above

∵ IWXI = $\sqrt{(1--2)^{2}+(4-8)^{2}+(-1--3)^{2}}=\sqrt{9+16+4}$

∴ IWXI = $\sqrt{29}$

The magnitude of WX is $\sqrt{29}$

Learn more:

You can learn more about the position of an object in brainly.com/question/10940255

#LearnwithBrainly

8 0

3 years ago

Read 2 more answers

Use De Moivre’s Theorem to compute the following: <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%288cos%284%20%5Cpi%20%2F5%

Kipish [7]

Hello here is a solution :

6 0

3 years ago