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TEA [102]
4 years ago
11

Use De Moivre’s Theorem to compute the following:

29%2B8isin%284%5Cpi%2F5%29%29%7D%20" id="TexFormula1" title="\sqrt[3]{(8cos(4 \pi /5)+8isin(4\pi/5))} " alt="\sqrt[3]{(8cos(4 \pi /5)+8isin(4\pi/5))} " align="absmiddle" class="latex-formula">

Mathematics
1 answer:
Kipish [7]4 years ago
6 0
Hello here is a solution : 

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Complete the square to transfer into vertex form and find the vertex: f(x)= x^2+6x-22
ioda

Answer:

To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of  

b

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(

b

2

)

2

=

(

−

3

)

2

Add the term to each side of the equation.

x

2

−

6

x

+

(

−

3

)

2

=

22

+

(

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Simplify the equation.

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x

2

−

6

x

+

9

=

31

Factor the perfect trinomial square into  

(

x

−

3

)

2

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(

x

−

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)

2

=

31

Solve the equation for  

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x

=

±

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The result can be shown in multiple forms.

Exact Form:

x

=

±

√

31

+

3

Decimal Form:

x

=

8.56776436

…

,

−

2.56776436

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Step-by-step explanation:

thats took a while lol

5 0
4 years ago
Read 2 more answers
How are a triangular pyramid and a rectangular pyramid different?
White raven [17]
Triangular pyramid has its base as a triangle, and a Rectangular pyramid has its base as a rectangle.
6 0
3 years ago
Read 2 more answers
(iii) If a, b, c are rational numbers, then<br>a x (b-c) #ax b-ax c. true or false ​
sp2606 [1]

Answer:

false

Step-by-step explanation:

answer:ab-ac=ab-ac

3 0
3 years ago
Select ALL expressions that are equivalent to -4(x+2)-2x+4
Vikki [24]

Answer:

c and d

Step-by-step explanation:

a

4 0
3 years ago
Hello guys, plz help me with this question ASAP! Plz show the working, THANK YOU BROTHER
RoseWind [281]

Answer:

5.5 min

Step-by-step explanation:

At time t=0 you have 72 grams

at time t = 22 min you have 4.5 grams.

Now

4.5/72 = (1/2)^(t/half-life)

and t=22, so

4.5/72 = (1/2)^(22/half-life)

taking log of both sides:

log(4.5/72)=(22/half-life)log(1/2)

solving for half-life gives half-life = 11/2 = 5.5min

8 0
3 years ago
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