Answer:
Solution given
Sin Q=opposite/hypotenuse=28/29
<u>28/29</u><u> </u><u>is</u><u>. </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u><u />
Answer:
1.) A
2.) D
3.) A
Step-by-step explanation:
Answer:
（3，-25）
Step-by-step explanation:
Some basic formulas involving triangles
\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa 2 =b 2+2 + c 2
−2bc cos α
\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab 2=
m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m b2 = 41(2a 2 + 2c 2-b 2)
b
Bisector formulas
\ \frac{a}{b} = \frac{m}{n} ba =nm
\ l^2 = ab - mnl 2=ab-mm
A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
\iits whatever A = prA=pr with r we denote the radius of the triangle inscribed circle
\ A = \frac{abc}{4R}A=
4R
abc
- R is the radius of the prescribed circle
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
Answer:
A = 
yd²
Step-by-step explanation:
the area ( A) of a rectangle is calculated as
A = length × width
= 
× 
= 
= yd²
