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MArishka [77]
2 years ago
10

2.) FIND EF.

Mathematics
1 answer:
Naddika [18.5K]2 years ago
8 0

The measure of EF from the given diagram is 6 units

<h3>Secant secant theorem</h3>

The theorem states that if two secants are drawn from an external point to a circle, then the product of the measures of one secant's external parts is the same as the product of the other external part.

Mathematically according to the given figure;

4(4+2x) = 5(5+x)

Expand

16 + 8x = 25 + 5x

Collect the like terms

8x - 5x = 25 - 16

3x = 9

Divide both sides by 3

3x/3=. 9/3

x = 3

Find EF

EF = 2x

EF = 2(3) = 6

Hence the measure of EF from the given diagram is 6 units

Learn more on secant theorem here: brainly.com/question/10732273

#SPJ1

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Answer:

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Step-by-step explanation:

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2t^2+1

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3 years ago
A rhombus has four 6-inch sides and two 120-degree angles. From one of the vertices of the obtuse angles, the two latitudes are
nikitadnepr [17]

Answer:

Area(A)=Area(C)= 9 in^{2}

Area(B)=13.2 in^{2}

Step-by-step explanation:

We begin with finding the angles a and b that from the drawing attached you can see that a=b.

Now, the sum of the internal angles of a rhomboid is equal to 360 degrees, with that we have:

120+120+a+b=360

240+2a=360

2a=120

a=60=b

Next, in the image you can see that the lines coming from the angle at the top 120 degrees vertex, divide the opposite sides by half, thus making two triangles with one side of 6 in and another of 3 in.

We can say from the drawing as well:

Area(A)+Area(B)+Area(C)=Area(rhomboid)

But, we can also say that Area(A)=Area(C)

So, starting with Area(A)

Area(A)=Area(triangle)=\frac{b*h}{2}=\frac{6*3}{2}=9 in^{2}

We can then calculate the area B, a rhomboid, or better, take the Total area of the figure and subtract the area of the two triangles.

Area(B)=Area(rhomboid)-Area(A)-Area(C)

Area(rhomboid)=b*h where b=6in and h is the perpendicular distance from the base to the top.

h=[tex]6*cos(30)=5.20in   The 30 degrees come from: 120-30-60=30, since the latitudes split the 120 angle in two equal parts and one that is the half of the obtuse angle.

Area(rhomboid)=5.20*6=31.2 in^{2}

Area(B)=Area(rhomboid)-Area(A)-Area(C)=31.2 in^{2}-9 in^{2}-9 in^{2}=13.2 in^{2}

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Ede4ka [16]

Answer: 58 years old

Step-by-step explanation:

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3 years ago
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Answer:

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