Answer:
Step-by-step explanation:
- -13x < 65
- x > - 65/13
- x > -5
- x = (-5, + oo)
Answer:
the angle of elevation is 12.56°
Step-by-step explanation:
the height of the ramp represents the opposite side and the length of the ramp the hypotenuse
we see that it has (angle, hypotenuse, opposite)
well to start we have to know the relationship between angles, legs and the hypotenuse
a: adjacent
o: opposite
h: hypotenuse
sin α = o/h
cos α= a/h
tan α = o/a
we choose the one with opposite and hypotenuse
sin α = o/h
sin α = 5ft / 23ft
sin α = 5/23
α = sin^-1 ( 5/23)
α = 12.56°
the angle of elevation is 12.56°
The height of Maury's room is 8.4 ans maury is 6.6 feet tall. The distance between the celling and Maury's head is exactly 1.8. She wants to hang the celling fan 1.875 feet away from the celling that is all the head room she has the celling fan would hit her head.
Answer:
The only two that share both of these qualities are the isosceles triangle and the isosceles right triangle.
Substitute
, so that
. Then the ODE is equivalent to

which is separable as

Split the left side into partial fractions,

so that integrating both sides is trivial and we get








Given the initial condition
, we find

so that the ODE has the particular solution,
