Answer:
Use this pencentage change formula:
New - Old
---------------- x 100
Old
Step-by-step explanation:
390 + 35.10 = 425.1 (New value)
So apply this to the formula:
425.1 - 390
--------------- x 100
390
<em>Which is = 9%</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em> </em><em>Cheers</em><em>!</em><em> </em><em>:</em><em>)</em>
Answer:
The value of N = 118
Step-by-step explanation:
750 = 6n + 42
move all the numbers that don't contain n to the right side
6n = 750 - 42
6n = 708
708 / 6 = 118
n = 118
plug the numbers back in
6 ( 118) = 708
708 = 708
plug the 42 back in
708 + 42 = 750
Option C
<u>SOLUTION:</u>
We need to find the value of B - CF
First find the value CF:
![CF=\left[\begin{array}{ccc}12&0&1.5\\1&-6&7\\\end{array}\right] \left[\begin{array}{ccc}-2&0\\0&8\\2&1\end{array}\right]](https://tex.z-dn.net/?f=CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%260%261.5%5C%5C1%26-6%267%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%260%5C%5C0%268%5C%5C2%261%5Cend%7Barray%7D%5Cright%5D)
![CF=\left[\begin{array}{ccc}12(-2)+0 *0+1.5*2&12*0+0.8+1.5*1\\1*(-2)+(-6)*0+7.2&1*0+(-6)*8+7.1\\\end{array}\right]](https://tex.z-dn.net/?f=CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%28-2%29%2B0%20%2A0%2B1.5%2A2%2612%2A0%2B0.8%2B1.5%2A1%5C%5C1%2A%28-2%29%2B%28-6%29%2A0%2B7.2%261%2A0%2B%28-6%29%2A8%2B7.1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![CF=\left[\begin{array}{ccc}-21&1.5\\12&-41\\\end{array}\right]](https://tex.z-dn.net/?f=CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-21%261.5%5C%5C12%26-41%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Now find value of B - CF:
![B-CF=\left[\begin{array}{ccc}2&8\\6&3\\\end{array}\right] -\left[\begin{array}{ccc}-21&1.5\\12&-41\\\end{array}\right]](https://tex.z-dn.net/?f=B-CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%268%5C%5C6%263%5C%5C%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-21%261.5%5C%5C12%26-41%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![B-CF=\left[\begin{array}{ccc}23&6.5\\-6&44\\\end{array}\right]](https://tex.z-dn.net/?f=B-CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D23%266.5%5C%5C-6%2644%5C%5C%5Cend%7Barray%7D%5Cright%5D)
∴ the value of B - CF is ![\left[\begin{array}{ccc}23&6.5\\-6&44\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D23%266.5%5C%5C-6%2644%5C%5C%5Cend%7Barray%7D%5Cright%5D)
<em>I hope this helps....</em>
The height of the kite will be 6.6 ft rounded to the nearest tenth.
<u><em>Explanation</em></u>
According to the below diagram, AB is the height of the kite and AC is the 12 ft line attached to it.
The line is pulled taut and casts a 10 ft shadow. That means BC = 10 ft
Now, in right angle triangle ABC, using <u>Pythagorean theorem</u>....

So, the height of the kite will be 6.6 ft rounded to the nearest tenth.