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3 years ago

100 POINTS+ BRAINLYEST❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

7 0

Step-by-step explanation:

The vertex form of a parabola can be written as

$y = {a(x - h)}^{2} + k$

where (h, k) are the coordinates of the parabola's vertex. The vertices of the functions are as follows:

a) (3, 5)

b) (-7, 3)

c) (4, 0)

d) (0, -1)

e) (-1, -5)

f) (-1, -5)

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(2x^2 - 5x + 3) - (-x2 + 4x - 5) A) x2 - x - 2 B) 3x2 - 9x - 2 C) 3x2 - x + 15 D) 3x2 - 9x + 8

Lelu [443]

Answer:

3x^2 -9x +8

Step-by-step explanation:

Hopefully this attachment will help you!!!

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6 0

4 years ago

Read 2 more answers

Find a solution to the following system of equations. –2x + y = –3 –x + 2y = 3

kvv77 [185]

-2x + y = -3.....multiply by -2
-x + 2y = 3
-----------------
4x - 2y = 6 (result of multiplying by -2)
-x + 2y = 3
----------------add
3x = 9
x = 9/3
x = 3

-2x + y = -3
-2(3) + y = -3
-6 + y = -3
y = -3 + 6
y = 3

solution is (3,3)

6 0

4 years ago

2(12-10)3-4+10 pls hurry

valkas [14]

Answer:

Step-by-step explanation:

6 0

3 years ago

Please someone help me to prove this..

Pachacha [2.7K]

Answer: see proof below

Step-by-step explanation:

Use the following Sum to Product Identities:

$\sin x+\sin y=2\sin \bigg(\dfrac{x+y}{2}\bigg)\cos \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\sin x-\sin y=2\cos \bigg(\dfrac{x+y}{2}\bigg)\sin \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\cos x+\cos y=2\cos \bigg(\dfrac{x+y}{2}\bigg)\cos \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\cos x+\cos y=-2\sin \bigg(\dfrac{x+y}{2}\bigg)\sin \bigg(\dfrac{x-y}{2}\bigg)$

Proof LHS → RHS

$\text{LHS:}\qquad \qquad \qquad \dfrac{\sin 5-\sin 15+\sin 25 - \sin 35}{\cos 5-\cos 15- \cos 25 + \cos 35}$

$\text{Reqroup:}\qquad \qquad \qquad \dfrac{(\sin 25+\sin 5)-(\sin 35 + \sin 15)}{(\cos 35+\cos 5)-(\cos 25 + \cos 15)}$

$\text{Sum to Product:}\quad \dfrac{2\sin \bigg(\dfrac{25+5}{2}\bigg)\cos \bigg(\dfrac{25-5}{2}\bigg)-2\sin \bigg(\dfrac{35+15}{2}\bigg)\cos \bigg(\dfrac{35-15}{2}\bigg)}{2\cos \bigg(\dfrac{25+15}{2}\bigg)\cos \bigg(\dfrac{25-15}{2}\bigg)-2\cos \bigg(\dfrac{35+5}{2}\bigg)\cos \bigg(\dfrac{35-5}{2}\bigg)}$ $\text{Simplify:}\qquad \qquad \dfrac{2\sin 15\cos 10-2\sin 25\cos 10}{2\cos 20\cos 15-2\cos 20\cos 5}$

$\text{Factor:}\qquad \qquad \dfrac{2\cos 10(\sin 15-\sin 25)}{2\cos 20(\cos 15-\cos 5)}$

$\text{Sum to Product:}\qquad \dfrac{\cos 10\bigg[2\cos \bigg(\dfrac{15+25}{2}\bigg)\sin \bigg(\dfrac{15-25}{2}\bigg)\bigg]}{\cos 20\bigg[-2\sin \bigg(\dfrac{15+5}{2}\bigg)\sin \bigg(\dfrac{15-5}{2}\bigg)\bigg]}$

$\text{Simplify:}\qquad \qquad \dfrac{\cos 10[2\cos 20\sin (-5)]}{\cos 20[-2\sin 10\sin 5]}\\\\\\.\qquad \qquad \qquad =\dfrac{-2\cos10 \cos 20 \sin 5}{-2\sin 10 \cos 20 \sin 5}\\\\\\.\qquad \qquad \qquad =\dfrac{\cos 10}{\sin 10}\\\\\\.\qquad \qquad \qquad =\cot 10$

LHS = RHS: cot 10 = cot 10 $\checkmark$

8 0

3 years ago

How many times can 14 go into 8574?

bearhunter [10]

612.4285714285714 is the answer

8 0

3 years ago