Answer:
A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:
A. closed at both ends
B. open at one end and closed at one end
C. open at both ends.
D. we cannot tell because we do not know the frequency of the sound.
The right choice is:
B. open at one end and closed at one end
.
Step-by-step explanation:
Given:
Length of the pipe, 
= 120 cm
Its wavelength 
= 480 cm
= 160 cm and 
= 96 cm
We have to find whether the pipe is open,closed or open-closed or none.
Note:
- The fundamental wavelength of a pipe which is open at both ends is 2L.
- The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.
So,
The fundamental wavelength:
⇒ 
It seems that the pipe is open at one end and closed at one end.
Now lets check with the subsequent wavelengths.
For one side open and one side closed pipe:
An odd-integer number of quarter wavelength have to fit into the tube of length L.
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
So the pipe is open at one end and closed at one end
.
The whole ends up being 42 ft².
Area of a triangle = 1/2 * base * height.
So that lil triangle piece is 1/2 * 2 * 3 = 1/2 * 6 = 3
Now we do the rectangle piece. Area of a rectangle = length * width
So that rectangle is 3 * 7 = 21
If you take away those two, you are left with a trapezoid.
Area of a trapezoid is 1/2 * (base 1 + base 2) * height
Base 1 is the width of the rectangle which is 3. Base 2 is the 6. The height is the given 11 feet minus the 7 feet from the length of the rectangle which is 4.
Plug all this in to the formula you get 1/2 * (6 + 3) * 4 = 1/2 * 9 * 4 = 1/2 * 36 = 18.
Now add all of your areas together;
21 + 3 + 18 = 24 + 18 = 42
Answer:
Read step by step explanation
Step-by-step explanation:
The owner already knows that the limit for the average time delivered pizzas is 38 minutes. So we conclude
1.-The resulting mean from sample data ( x ) ( 27 customers) need to be smaller than 38 minutes, any value of sample above 38 minutes means more time for the delivery action and will indicate a failure for the future project
2.-As sample size is smaller than 30 the test has to be t-student one tail test to the left
Test hypothesis
Null hypothesis H₀ x = 38
Alternative hypothesis Hₐ x < 38
We should test at a significance level α = 0,05 (α = 5%)
If the result of the test is to accept H₀ delivery project won´t be implemented, if on the other hand, H₀ is rejected then in the condition of the alternative hypothesis we accept Hₐ the sample indicates that we have a smaller average time than 38 minutes.
1-rotational
2-rotational
3-rotational
4-neither
(I’m like 99% sure)
<span>A value is in the domain if there is a point on the graph of the function at that x-value</span>
