Our quadratic polynomial function is:
f(x) = 4x^2 + 2x + 5
our linear binomial form is:
x - a = -2
hence:
a = x + 2
and so we have:
f(x) = 4x^2 + 2x + 5
f(a) = 4(x + 2)^2 + 2<span>(x + 2)</span> + 5
= 4(x^2 + 4x + 4) + 2x + 4 + 5
f(a) = 4x^2 + 18x + 25
Answer:
Only option A is correct.
Step-by-step explanation:
From the given figure it is noticed that the vertices of hyperbola are (0,8) and (0,-8). It is a vertical hyperbola.
It means a=8.
From the rectangle we can say that the value of b is 6.




The focus of a vertical hyperbola are (0,c) and (0,-c). So, the focus of hyperbola are (0,10) and (0,-10).
Therefore option A is correct.
Asymptotes of a vertical hyperbola are



Directrix of a vertical hyperbola are



Only option A is correct.
(n-7) (n-7) will be your answer
n x n = n²
n x -7 = -7n
n x - 7 = -7n
-7n +(-7n) = -14n
-7 x -7 = 49
(n-7)² is your answer
hope this helps
and if you are doing the other thing
n = 7, 7
hope this helps
the answer is C.
by the formula vertex (xv,yv) y=a(x-xv)²+yv
Answer:
We need to know what the program is...
Step-by-step explanation:
This question is literally unanswerable as some programs last 2 seconds and some would last thousands of years. More context as to what the program is please.