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3 years ago

14

When Ethan began a weight loss program, he weighed 284 pounds. He was able to lose exactly 3 pounds every month. How much would

weigh 41 months after starting the weight loss program? Round to the nearest tenth (if necessary)

1 answer:

OlgaM077 [116]3 years ago

8 0

Answer:

161 pounds

Step-by-step explanation:

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HELP ME JUST ANSWER PLZ IM SUFFERING I WILL GIVE YOU BRAINLYEST OR WHATEVER

Gre4nikov [31]

Answer:

534.07in squared is what I got for the surface area

Step-by-step explanation:

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3 years ago

Please find question in photo below. I’m revising for a test I have in a few days, and I can’t figure this out. Please help!

Temka [501]

$\large{\rm{\underline{\underline{Answer:}}}}$

a) <u>n² + 6 </u>

~Here n is the number of term. So, put n = 1,2,3,4.... to get the term.

If n = 1, first term = 1² + 6 = 7
n = 2, second term = 10
n = 3, third temm = 15
n = 4, fourth term = 22
n = 10, tenth term = 106

b) <u>3n²</u>

If n = 1, first term = 3
n = 2, second term = 12
n = 3, third term = 27
n = 4, fourth term = 48
n = 10, tenth term = 300

3 0

3 years ago

The length of a rectangle is 16 inches. if the width is 25% of its length, what is the perimeter of the rectangle

Leokris [45]

Answer:

Perimeter = 40 inches

Step-by-step explanation:

Length = 16 inches

Width = 25% of length (16)

= 25% of 16

25% = 1/4

Width = 1/4 x 16

= 4 inches

Length = 16 inches

Width = 4 inches

Perimeter of a rectangle = length + length + width + width:

= 16 + 16 + 4 + 4

= 32 + 8

= 40

PERIMETER = 40 inches

So glad I could help :)

4 0

3 years ago

Write the next three terms of the following sequence 4,5,7,10,14

Law Incorporation [45]

4,5,7,10,14=19,25, 32

8 0

3 years ago

Find the discriminant and determine the nature of the roots to the quadratic equation

Katen [24]

№17
$x^{2} +6x-7=0 \\ D=6 ^{2} -4*(-7)=36+28=64=8 ^{2} \\ \\ x_{1} = \frac{-6+8}{2} =1 \\ \\ x_{2} = \frac{-6-8}{2} =-7$
Answer: x₁ = 1
   x₂ = - 7

№18
$2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\ \\ D= -3 ^{2} -4*2=9-8=1 \\ \\ x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\ \\ x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5$
Answer: x₁ = 1
     x₂ = 0,5.

№19
$2 x^{2} -4x-5=0 \\ D=-4 ^{2} -4*2*(-5)=16+40=56 \\ \\ x_{1}= \frac{4+ \sqrt{56} }{2*2} = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5} \\ \\ x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} - \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} 
$
Answer: x₁ = 1 + √3.5
     x₂ = 1 - √3.5

3 0

4 years ago