C.) Keep your body in contact with the metal area of the computer
Generally, you want to keep contact with something metallic with clear path-to-ground. For instance, painted metal can do the job, but not as efficiently.
There are other ways to go about avoiding ESD, but this is the best option given in your question.
B- the amount you pay the health insurance company every month for coverage
Answer:
wireless LAN
Explanation:
An extranet is a network area where people or corporate partners external to the company access data. An intranet simply describes the network area that is normally accessed only by internal personnel. The wired LAN is affected by BYODs (bring your own devices) when the devices attach to the wired network. A college wireless LAN is most likely used by the tablet and smartphone. A wireless WAN would more likely be used by college students to access their cell provider network.
Answer:
This is the complete correct program:
#include <stdio.h>
#include<sys/types.h>
#include<unistd.h>
int value = 128;
int main()
{
pid_t pid;
pid=fork();
if (pid==0) /* child process */
{
value +=8;
return 0; }
else if (pid > 0) {/* parent process */
wait (NULL);
printf ("PARENT: value =%d\n" ,value); /* LINEA */
return 0;
}
}
The output of the LINE A is:
PARENT: value = 128
Explanation:
The fork() function used in the program creates a new process and this process is the child process. The child process is same as the original process having its own address space or memory.
In the child process the value of pid is 0. So the if condition checks if pid==0. Then the child process adds 8 to the value of its variable according to the following statement
value +=8;
Now the original process has value = 128. In else if part the parents process has the value of pid greater than zero and this portion of the program is of the parent process :
else if (pid > 0)
{ wait (NULL);
printf ("PARENT: value =%d\n" ,value);
return 0; }
So the value 128 is printed at the end in the output.
wait(NULL) is used to wait for the child process to terminate so the parent process waits untill child process completes.
So the conclusion is that even if the value of the variable pid is changed in the child process but it will not affect the value in the variable of the parent process.
You are going to select 5 keyboards, from a set of 25 defective keyboards. When you select the first keyboard it may be have either electrical deffects or mechanical deffect, this is two possibilities. The same happens with the second, third, fourth and fifth selection. Then each selection has 2 different possibilities, and the number of possibilities are: 2*2*2*2*2 = 32.
But that is considering that the order matters. This is that it is different that the first has electrical deffects and the others have mechanical defects than the second has mechanical electrical deffects and the other has mechanical deffects.
If you the order is not relevant, then the only different outcomes are:
1) 5 with electrical deffects
2) 4 with electrical deffects and 1 with mechanical deffects
3) 3 with electrical deffects and 2 with mechanical deffects
4) 2 with electrical deffects and 3 with mechanical deffects
5) 1 with electrical deffects and 4 with mechanical deffects
5) 5 with mechanical deffects.
In this case the answer is 6 different ways.
Answer: 6
