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Marta_Voda [28]
3 years ago
13

What is the image of (4,2) ?

Mathematics
1 answer:
Alinara [238K]3 years ago
7 0

- don't know what you mean, but maybe the graph?

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Using the following graph answer A-C
krek1111 [17]

Answer:

The answer to your question is below

Step-by-step explanation:

a) Find to points of the line and find the equation of the line.

A ( 0, -4)            B (2, 0)

slope = m = \frac{0 + 4}{2 - 0}

     m = \frac{4}{2}

            m = 2

Line equation

                      (y - y1) = m (x - x1)

                      (y - 0) = 2(x - 2)

                            y = 2x - 4

Write the line as an inequality

                           y ≥ 2x - 4

b) Yes, (2,0) is a solution of the inequality

                           y ≥ 2x - 4

                           0 ≥ 2(2) -4

                           0 ≥ 4 - 4

                           0 ≥ 0              This is true

c) No, (4, -2) is not a solution.

                          y ≥ 2x - 4

                         -2 ≥ 2(4) - 4

                         -2 ≥ 8 - 4

                         -2 ≥ 4               This is false

8 0
3 years ago
If a= b^2/3 and b= c^3/4; what is the relation between a and c?
Lorico [155]

Answer: a = c^(1/2) which is the first answer choice of the list

Work Shown:

a = b^(2/3) ... given equation

a = (c^(3/4))^(2/3) ... replace b with c^(3/4)

a = c^((3/4)*(2/3)) .... multiply exponents

a = c^(1/2) .... Simplify; note the 3's cancel, also 2/4 turns into 1/2

6 0
3 years ago
^^ this is the last oneeee
natka813 [3]
I believe the measurement of AB is 30 degrees
8 0
3 years ago
Read 2 more answers
PLEASE HELP!! this is due soon and i rlly need help
egoroff_w [7]

Answer:

Solution given:

r=3km

area of sector bounded by a 90° arc=90°/360°*πr²

=¼*π*3²

=<u>9/4 π or 7.068km²</u>

is a required answer

6 0
3 years ago
Read 2 more answers
Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl
Kazeer [188]

Answer: 10 ft

Explanation

As two right triangles (a triangle with a 90º angle) are formed, to know the distance between AB we have to calculate BC, AC and subtract.

0. Calculating BC

We have a 30º angle and an adjacent side 5√3ft (as the hypotenuse is the side opposite to the 90º angle). Thus, using the tangent function where:

\tan\theta=\frac{opposite}{adjacent}

we can find the opposite side, which is BC. Replacing the values and simplifying we get:

\tan(30\degree)=\frac{BC}{5\sqrt{3}}BC=5\sqrt{3}\tan(30\degree)BC=5ft

Thus, the segment BC measures 5ft.

<em>2. Calculating segment AC</em>.

In this case, our hypotenuse changes. However, we are still looking for the opposite side. Using the tangent function as before we get:

AC=5\sqrt{3}\tan(60\degree)AC=15

<em>3. Calculating the distance between A and B</em>

AC-BC=15-5=10ft

6 0
1 year ago
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