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viktelen [127]
3 years ago
6

3.) T4.T4 Simply this for me to plz look at the pic

Mathematics
1 answer:
nikdorinn [45]3 years ago
4 0

Answer:

t^8

Step-by-step explanation:

t^4 times t^4

exponents you add.

4 + 4 = 8

t^8

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A club is accepting new members. 36 girls sign up but the club can only accept 24 girls. What percentage of the girls will be ac
maks197457 [2]

Answer:

75%

36= 100  16= 50%  8= 25%

Lets make percentage = P

(8x x 3x -x ) = ( P x 3x -x) 5 /1/20

=  (8 *3) = P x 3 ) x 5 /1/20

reduce = P x 3 x 8 = 24 x 3 x 5 / 1/20

360/24  = 15  x 1/20

5 x 15 = 75%

Step-by-step explanation:

7 0
3 years ago
Solve for x: -5bracket(-3x+1)=-45
NikAS [45]

Answer:

Step-by-step explanation:

Equation

-5(-3x+1)=-45     If this is not correct, leave a comment please.

Solution

-5(-3x+1)=-45                     Divide by -5

-5(-3x + 1)/5 = -45/-5              

(-3x + 1) =  9                       Remove the brackets

-3x + 1 = 9                          Subtract 1 from both sides

-3x + 1 - 1 = 9 - 1                 Simplify

-3x = 8                               Divide by  -3

-3x/-3 = 8/-3

x = -8/3

or

x = -2.66

or

x = - 2 2/3

8 0
2 years ago
A jet ski company charges a flat fee of $24.00 plus $2.25 per hour to rent a jet ski. Another company charges a fee of $23.00 pl
KatRina [158]
Let the number of hours the ski jet was rented be x, then
For company A, Cost = 2.25x + 24
For company B, Cost = 2.75x + 23

Fro the cost to be the same: 2.25x + 24 = 2.75x + 23
2.75x - 2.25x = 24 - 23
0.5x = 1
x = 1/0.5 = 2
x = 2

The cost are the same after 2 hours.
5 0
3 years ago
If you reflect ABCD across x-axis, what will be the coordinates of A’ and C’
disa [49]

Answer:

A (1, -5), B (2, -5)

8 0
4 years ago
Read 2 more answers
Calculate the standard deviation of the following data. 3, 4, 5, 6, 2, 3, 12, 79, 5
malfutka [58]
The answer to this is 23.42 (For population, SD)

The data given as a whole is called UNGROUPED data. The standard deviation can be computed with the formula: 

\sqrt{\dfrac{\sum(x_i-\bar{x})^2}{n}}

To do this, you need to first figure out the following:

Mean (\bar{X}) =?
The sum of \sum(x_i-\bar{X})^{2} =?

You need to write down your data in a table, but before you can do this, you need to first find out what the mean is and you can do this by adding up all the data and dividing it by the number of observations:

\bar{X} = \frac{sum of all data}{number of observations}
\bar{X} = \frac{3+4+5+6+2+3+12+79+5}{9} = \frac{119}{9}= 13.22

So we subtract the mean from each data to fill in the second column. I'll use the first raw data to make the first row as an example here:
(x-\bar{X}= 3-13.22=-10.22) 

For the third column, you just need get the square of the second column.
(x_i-\bar{X})^{2} =(-10.22)^{2}= 104.4484

For this table, let x be raw data and X be \bar{X}:

  x   |    (x-X)        |    (x-X)²     
  3   |    -10.22     |   104.4484         
       |                   |
  4   |   -  9.22      |     85.0084
       |                   |
  5   |   -  8.22      |     67.5684
       |                   |
  6   |   -  7.22      |     52.1284
       |                   |
  2   |     - 11.22   |     125.8884
       |                   |
  3   |    -10.22     |     104.4484
       |                   |
12   |   -  1.22      |         1.4884 
       |                   |
79   |    65.78      |   4327.0084
       |                   |
 5    |    -  8.22     |       67.5684
                 
REMEMBER: The Σ means "the sum of" to get Σ(x-X)² Add the values in the third column to get the sum of (x-X)² and you will get 4,935.5556 

Now all you have to do is input it into your equation:

sd=\sqrt{\dfrac{\sum(x_i-\bar{x})^2}{n}}
\sqrt{\frac{4935.5556}{9}}
\sqrt{548.39506666}
23.42

The standard deviation is 23.42

4 0
4 years ago
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