I hope this helps you
small a
larger 2a-1
a+2a-1=41
3a=42
a=14
2a-1=2.14-1=27
B. A quadrilateral equals 360, a triangle 180. 360-180=180
<span>5,286÷3
how many digits will the classroom number have
Notice that we have 4 digits as dividend with a place value of thousands as the
highest and to be divided with our divisor that have only 1 digit with a place value
of ones.
Now, let’s see how many digit will our quotient have:
=> 5 286 / 3
=> 1 762 is the quotient, it has still 4 digit with a place value of
thousands.
To check simply multiply our quotient and divisor.</span>
5 object which are longer than your hand- span in my surrounding is Note book, Laptop, Window, Curtain, Table.
Hand span is a measure of distance from the tip of the thumb to the tip of the little finger with the hand fully extended.
Hand span is a measure that has been used for many years. By placing the hand on the edge of a piece of paper and marking the tips of the thumb and little finger, the student can measure a straight line. This is a better method than placing the hand directly on the ruler.
Hand span and cubit are not used as standard units of length because their sizes vary from person to person. So, two different persons may give different measurements for the same length, which is not desirable for a standard unit.
Measure using yours hands and write as per your hand-span measurement.
Therefore,
5 object which are longer than your hand- span in my surrounding is Note book, Laptop, Window, Curtain, Table.
Find out more information about hand span here
brainly.com/question/993795
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Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

(1)
By Quadratic Formula:

,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.