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VladimirAG [237]
3 years ago
9

4 1/4 + 1 2/3 equals​

Mathematics
1 answer:
oee [108]3 years ago
3 0

Answer:

5.91666666667

Step-by-step explanation:

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Perform the indicated operations(7n^2 - 6) - (6n^2 + 9) - (7n + 6)
DerKrebs [107]

Answer:

n²-7n-21

Explanation:

Given the expression:

\mleft(7n^2-6\mright)-(6n^2+9)-(7n+6)

First, open the brackets:

=7n^2-6-6n^2-9-7n-6

Next, bring the like terms together and simplify:

\begin{gathered} =7n^2-6n^2-7n-6-9-6 \\ =n^2-7n-21 \end{gathered}

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1 year ago
Y=-16t^2+8t
disa [49]

Answer:

1/4th of a second, or .25 seconds

Step-by-step explanation:

graphed it.

3 0
2 years ago
Your employer has 600 business cards printed to you,and you gave away 280 of them to the nearest hundreth what percentage of the
Snowcat [4.5K]
I need point i dont
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3 years ago
Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball
Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and 51\frac{1}{3} yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from 51\frac{1}{3} yards.

\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}

Let us have a common denominator.

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}  

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}

\text{1 yard}=3\text{ feet}

\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}

\frac{28}{3}\text{ yards}=28\text{ feet}

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0
4 years ago
If y = -6cosx, what is the amplitude?
aniked [119]

 

\displaystyle\bf\\y=-6cos\,x\\\\\textbf{is equivalent to:}\\\\y=6cos(x+\pi)\\\\\textbf{where 6 is the maximum value or amplitude}\\\\\implies~~~\boxed{\bf~amplitude=6}

 

8 0
3 years ago
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