In hexadecimal/base-16, we have B₁₆ = 11, C₁₆ = 12, and D₁₆ = 13, so
4D₁₆ = 4 × 16¹ + 13 × 16⁰ = 77
and
BC2₁₆ = 11 × 16² + 12 × 16¹ + 2 × 16⁰ = 3010
The answer should be 3x^2 -13x+7.
Answer:
The Answer is: The first number is 10 and the second number is 8.
Step-by-step explanation:
Let f = first number and s = second number.
The first number is 2 larger than the second:
f = n + 2
The numbers times each other is 80:
f * n = 80
Substitute the value of f, which is (n + 2):
n(n + 2) = 80
n^2 + 2n = 80
n^2 + 2n - 80 = 0
(n + 10)(n - 8) = 0
n^2 + 10n - 8n - 80 = 0, so the first number is 10 and the second one is 8.
Another method, just from thinking about it:
factor 80:
8 * 10, is the first factoring I thought of. I then noted that the difference between the two is 2 and if you multiply them they equal 80.
Hope this helps! Have an Awesome Day!! :-)
Definition: The <u>probability</u> of an event happening is expressed as a fraction between 0 and 1.
Example: The <u>chance</u> that you roll a 4 on a die is 1
Answer:
Sure!
Step-by-step explanation:
