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svetlana [45]
3 years ago
10

What is 3gh 2 x 4g 3h 3

Mathematics
1 answer:
Alexus [3.1K]3 years ago
5 0

Answer:

(3•22g4h5)

Step-by-step explanation:

Step 1:  ((3gh2 • 4) • g3) • h3

Step 2:   ((3•22gh2) • g3) • h3

Step 3:   3.1 h2 multiplied by h3 = h(2 + 3) = h5

Final answer:   (3•22g4h5)

(IF THIS HELPED PLEASE GIVE BRAINLIEST OR RATE IT 5 STARS!)

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Find the area of the trapezoid when height = 5in, base1 = 12in, and base2 = 15in.
myrzilka [38]
A= (a+b)/2*h
A=(12+15)/2*5
A=(27/2)*5
A=13.5*5
A=67.5in
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3 years ago
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What is the value of this expression when x=2 and y=-4? -3(x-y)2
Llana [10]

Answer:

-108

Step-by-step explanation:

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2 years ago
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How can you use models to explain why 3.1 = 3.10
Andrej [43]
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4 0
3 years ago
Anyone know how to do this
svlad2 [7]

Answer:

The area of the rectangle on the left side is

9cm \:  \times 4cm = 36 {cm}^{2}

The area of the bottom rectangle is

6cm \times 2cm = 12 {cm}^{2}

The total area of the composite figure will be

36 {cm}^{2}  + 12 {cm}^{2}  = 48 {cm}^{2}

Step-by-step explanation:

The area of any given rectangle can be found by multiplying the length of that rectangle by its width. The rectangle on the left side has a length of 9cm but the width is unknown. To find the width, we subtract 6cm from the width of the bottom rectangle: 10cm. And that gives us 4cm.

Therefore, we can now calculate the area to be: length × width = 9cm × 4cm = 36cm²//

The area of the bottom rectangle can be found similarly by multiplying the length: 2cm by the width: 6cm of that rectangle. And the result gives us: 2cm × 6cm = 12cm²//

The total area of the composite figure is calculated by adding the results from the left and bottom rectangles together. And that gives us: 36cm² + 12cm² = 48cm²//

8 0
3 years ago
How many inflection point(s) do you see ?
dimulka [17.4K]

Answer:

  7

Step-by-step explanation:

There is a point of inflection at each point where the graph crosses the line y=2. There are 7 points of inflection shown.

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A point of inflection is where the graph changes from being concave downward to concave upward, or vice versa. For a sine function, that is everywhere the function crosses its midline.

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3 years ago
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