3 years ago

Math question

Mathematics

1 answer:

Alika [10]3 years ago

8 0

Answer:

I believe the answer is true, please let me know if I am wrong.

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Please help me answer the questions in the picture

svet-max [94.6K]

Study the function properly

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3 years ago

7z² 5z⁴ d³ d⁸ what strategy to simplify or model

Shalnov [3]

Answer:

35z at the power of 6 times d at the power of 11

Step-by-step explanation:

add the z's power together then the d's power

4 0

3 years ago

(4,?) is on the line below. find the other half of the coordinate. y=2/7x+3

Savatey [412]

Since we have (4,?) we know x=4. Substitute this into the equation and solve for y.

y= 2/7*4+3

y= 2/7*4/1+3

y= 8/7+3

y= 8/7 + 3/1

y= 16/14 + 42/14

y= 58/14 or 4.14

8 0

3 years ago

The answer to the question.

Dmitriy789 [7]

Answer:

0-4=-4 -4-9=-13

7 0

3 years ago

The box at the right is a cube with edges that measure 2 feet. The sides of the triangle inside the cube are a diagonal of a fac

zvonat [6]

Answer:

$Area = 2 \sqrt{2}$

Step-by-step explanation:

Given

$Length_1 = 2$

$Length_2 = \sqrt{2^3}$

Required

Determine the area of the triangle

The given lengths represent the height and base length of the triangle.

So, the area is;

$Area = \frac{1}{2} * Length_1 * Length_2$

Substitute values for Length1 and Length2

$Area = \frac{1}{2} * 2 * \sqrt{2^3}$

$Area = \frac{2}{2} * \sqrt{2^3}$

$Area = 1* \sqrt{2^3}$

$Area = \sqrt{2^3}$

Express 2^3 as 2 * 2 * 2

$Area = \sqrt{2*2*2}$

$Area = \sqrt{4*2}$

Split

$Area = \sqrt{4} *\sqrt{2}$

$Area = 2 *\sqrt{2}$

$Area = 2 \sqrt{2}$

6 0

3 years ago