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3 years ago

15

Queston

2 answers:

Verdich [7]3 years ago

6 0

Answer:

$94

Step-by-step explanation:

An item is on sale $75

After a 20% discount was removed

The original amount of the item before discount was $94

Therefore 20%, of $94 is $75

Maru [420]3 years ago

3 0

Answer:

$60

Step-by-step explanation:

0.80 x 75 = $60

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In 1 hour Samantha can make 6 beaded bracelets. In 3 hours she can make 18 bracelets. How many can she make in 4 fours? PLEASE P

Step2247 [10]

Basically Samantha makes six bracelets per hour, so:
After 1 hour she makes 6
After 2 hours she makes 12
After 3 hours she makes 18
After 4 hours she makes 24, therefor the answer is B

This can also be modelled by the equation B = 6t, where B is the number of bracelets and t is the number of hours, so:
B = 6(4) = 24

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2 years ago

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3 years ago

6r-2(r+8)=11<br> Solve equation

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3 years ago

6*(2x+3)-(4x+2)=32 what is X?

nydimaria [60]

Answer:

6*(2x+3)-(4x+2)=32

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3 0

3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

2 years ago