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3 years ago

Queston

Mathematics

2 answers:

Verdich [7]3 years ago

6 0

Answer:

$94

Step-by-step explanation:

An item is on sale $75

After a 20% discount was removed

The original amount of the item before discount was $94

Therefore 20%, of $94 is $75

Maru [420]3 years ago

3 0

Answer:

$60

Step-by-step explanation:

0.80 x 75 = $60

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This is Q2:5 Weekly Math Review

mezya [45]

Answer:

28.50+x or 28.50x

Step-by-step explanation:

6*4.75=28.50

6*x=6x or x

7 0

3 years ago

Read 2 more answers

The Martinez family went to the movies and paid $60 for two adult tickets and three children’s tickets. The Wright family consis

Pepsi [2]

Answer:

a = $13.5

Step-by-step explanation:

Let a = adult tickets

Let c = children tickets

Translating the word problem into an algebraic equation;

For the Martinez family;

2a + 3c = $60

For the Wright family;

3a + 5c = $95.5

Thus, the simultaneous equations are;

$2a + 3c = $60$ ..........equation 1

$3a + 5c = $95.5$ .........equation 2

We would use substitution method to solve;

From equation 2, we make a the subject of formula;

3a = 95.5 - 5c

a = (95.5 - 5c)/3

Substituting the value of "a" into equation 1, we have;

2[(95.5-5c)/3] + 3c = 60

Multiplying all through by 3;

2(95.5 - 5c) + 9c = 180

191 - 10c + 9c = 180

191 - c = 180

c = 191-180

c = $11

To find the value of a;

2a +3c = 60

Substituting the value of "c" into the equation, we have;

$2a + 3(11) = 60$

$2a + 33 = 60$

$2a = 60 - 33$

$2a = 27$

$a = \frac{27}{2}$

a = $13.5

Therefore, the cost of an adult movie ticket is $13.5.

5 0

3 years ago

The distribution of heights for adult men in a certain population is approximately normal with mean 70 inches and standard devia

KengaRu [80]

Answer:

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12]

Step-by-step explanation:

I beleive those options corresponds to another question, i will ignore them. We want to know an interval in which the probability that a height falls there is 0.8.

In such interval, the probability that a value is higher than the right end of the interval is (1-0.8)/2 = 0.1

If X is the distribuition of heights, then we want z such that P(X > z) = 0.1. We will take W, the standarization of X, wth distribution N(0,1)

$W = \frac{X-\mu}{\sigma} = \frac{X-70}{4}$

The values of the cumulative distribution function of W, denoted by $\phi$ , can be found in the attached file. Lets call $y = \frac{z-70}{4}$ . We have