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aev [14]
3 years ago
10

I need help on math. It’s trinomials 25y^2-60y+36

Mathematics
1 answer:
Verdich [7]3 years ago
3 0

Answer:

(5y-6)^2

Step-by-step explanation:

Note that the polynomial 25y^ 2  −60y+36 is a perfect square trinomial, so we will use the following formula.

A ^2 −2AB+B^2 =(A−B) ^2

 

In this example we have A=5y and B=6 so,

25y^2 −60y+36=(5y−6)^2

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3 years ago
Is the relationship shown by the data linear? x -9, -5, -1, 3 y -2,-7,-12, -17
Temka [501]
                x               y
            ------           -----
              -9              -2
             -5               -7
             -1              -12
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ur x's all have a difference of 4, and ur y's all have a difference of -5...so yes, this is linear with a slope of (-7+2) / (-5 + 9) = -5/4
5 0
4 years ago
13 and 15<br><br>solve each problem by graphing and slope intercept​
mylen [45]

Answer: The answers are 13. (A) and 14. (B).

Step-by-step explanation: The calculations are as follows:

(13) The given equations are

y=-\dfrac{3}{8}x-6,\\\\\\y=-\dfrac{13}{8}x+4.

In the attached figure (a), these two lines are drawn. We can see that The lines intersect at the point P(8, -9). So, the solution to the pair of equations is (8, -9).

Thus, the correct option is (A).

(14) The given equations are

y=-\dfrac{1}{7}x-1,\\\\\\y=-x+5.

In the attached figure (b), these two lines are drawn. We can see that The lines intersect at the point Q(7, -2). So, the solution to the pair of equations is (7, -2).

Thus, the correct option is (B).

7 0
3 years ago
Simplify the expression cos x cot x+ sin x please select the best answer from the choices provided a.0, b.csc x, c. Tan x, d sec
expeople1 [14]

Answer:

cot x = \frac{cos x}{sin x}

cos x \frac{cos x}{sin x} + sin x

\frac{cos^2 x}{sin x} +sin x

sin^2 x + cos^2 x =1

Solving for cos^2 x we got cos^2 x =1 -sin^2 x and replacing this we got:

\frac{1-sin^2 x}{sin x} +sin x

\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x

csc x -sin x + sin x = csc x

And then the best option for this case would be:

b.csc x

Step-by-step explanation:

For this case we have the following expression given:

cos x cot x + sin x

We know from math properties that the definition for cot is cot x = \frac{cos x}{sin x}

If we use this definition we got:

cos x \frac{cos x}{sin x} + sin x

\frac{cos^2 x}{sin x} +sin x

Now we can use the following identity:

sin^2 x + cos^2 x =1

Solving for cos^2 x we got cos^2 x =1 -sin^2 x and replacing this we got:

\frac{1-sin^2 x}{sin x} +sin x

\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x

csc x -sin x + sin x = csc x

And then the best option for this case would be:

b.csc x

4 0
4 years ago
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