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3 years ago

How do I work this problem out?

Mathematics

1 answer:

Anni [7]3 years ago

6 0

This is asking for the cube root of 64. Another way of phrasing this is "What number cubed is equal to 64?" We know that 2³ is 8, so it must be a number greater than 2. 3³ is 27, it must be larger. 4³ is equal to 64, so 4 is your answer.

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Adele has 3 64-ounce cartons of orange juice and 3 48-ounce cans of apple juice. How much juice does she have altogether?

ale4655 [162]

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2 years ago

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schepotkina [342]

Answer:

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Step-by-step explanation:

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3 years ago

Find the solution of the system of equations.<br>6x + 8y = -8<br>x + 4y = 4<br>( , )

ladessa [460]

Answer:

the solution is (-4, 2)

Step-by-step explanation:

6x + 8y = -8

x + 4y = 4

... can be solved using elimination by addition and subtraction, among other methods. Multiply the second equation by -2 to obtain

6x + 8y = -8

-2x - 8y = -8

Combining these results in

4x = -16. Thus, x = -4.

Substituting -4 for x in x + 4y = 4 results in

-4 + 4y = 4, or 4y = 8, or y = 2

Then the solution is (-4, 2)

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3 years ago

What are the factors of 68

elixir [45]

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4 0

3 years ago

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Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.

Levart [38]

Answer:

The standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Step-by-step explanation:

We know that:

$4p\left(y-k\right)=\left(x-h\right)^2$ is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

$x^2\:+\:10x\:+\:6y\:=\:47$

Rewriting the equation in the standard form

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

where

vertex (h, k) = (-5, 12)

7 0

2 years ago