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Novosadov [1.4K]
2 years ago
10

If C=5/9(F-32), what is F when C=20?

Mathematics
2 answers:
siniylev [52]2 years ago
8 0
20 = 5 / 9(F-32)
f = 68
OLEGan [10]2 years ago
5 0
F = 68

Hope this helps
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Mr. Clark has a tank that holds 55,000 milliliters of gas. He poured some gas into three containers equally. There were 19,864 m
Temka [501]

Answer:

35,136 ml

Step-by-step explanation:

The tank holds 55,000ml. Mr. Clark poured some gas into 3 container, and at the end there the tank had 19,864. To find how much gas was poured out of the tank it is the same as asking how much gas he poured in the 3 containers, all together. We have to find the difference, subtraction:

55,000 - 19,864 = 35,136ml were poured in the 3 containers or amount of gas poured out of the tank.

3 0
3 years ago
What is the domain of the following function? {(3, 10), (5, 8) (10, 12), (15, 19)}
solong [7]

Answer:

3, 5, 10, 15

Step-by-step explanation:

I hope its help

3 0
3 years ago
In a test of the effectiveness of garlic for lowering​ cholesterol, 8181 subjects were treated with raw garlic. Cholesterol leve
xz_007 [3.2K]

Answer:

With garlic​ treatment, the mean change in LDL cholesterol is not greater than 0.

Step-by-step explanation:

The dependent <em>t</em>-test (also known as the paired <em>t</em>-test or paired samples <em>t</em>-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

In this case a paired <em>t</em>-test is used to determine the effectiveness of garlic for lowering​ cholesterol.

A random sample of 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: With garlic​ treatment, the mean change in LDL cholesterol is not greater than 0, i.e. <em>d</em> ≤ 0.

<em>Hₐ</em>: With garlic​ treatment, the mean change in LDL cholesterol is greater than 0, i.e. <em>d</em> > 0.

The information provided is:

\bar d=0.40\\SD_{d}=16.2\\\alpha =0.01

Compute the test statistic value as follows:

t=\frac{\bar d}{SD_{d}/\sqrt{n}}\\\\=\frac{0.40}{16.2/\sqrt{81}}\\\\=0.22

The test statistic value is 0.22.

Decision rule:

If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the <em>p</em>-value of the test as follows:

p-value=P(t_{n-1}>0.22)\\=P(t_{80}>0.22)\\=0.4132

*Use a <em>t</em>-table.

The <em>p</em>-value of the test is 0.4132.

<em>p-</em>value= 0.4132 > <em>α</em> = 0.01

The null hypothesis was failed to be rejected.

Thus, it can be concluded that with garlic​ treatment, the mean change in LDL cholesterol is not greater than 0.

3 0
3 years ago
Solve this for me plzzzz and thxxx
Shkiper50 [21]

answer: (-6,6) that's youre answer

5 0
3 years ago
Read 2 more answers
Find the value of x.
grandymaker [24]
I think X is 2. But I am not sure, cuz I don’t know what you teacher is really asking you to do.

8 0
2 years ago
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