How many months until they price is the same in 22 + 24.50x = 47 + 18.25x

Need that help.......plz

Anika [276]

For Question Number one
(2+10)²+4=148

Question Number two:
(6+5)×(8-6)=22

5 0

3 years ago

In ΔLMN, n = 910 inches, ∠L=64° and ∠M=31°. Find the length of l, to the nearest 10th of an inch

mr_godi [17]

Answer:

821

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Which of the following is a like radical to mc001-1.jpg?

mixer [17]

You haven't provided the expression or the choices, therefore, I cannot provide an exact answer.
However, I'll try to help you understand the concept so that you can solve the question you have

Like radicals are characterized by the following:
1- They both have the same root number (square root, cubic root , ...etc)
2- They both have the same radicand (meaning that the expression under the root is the same in both radicals)

Examples of like radicals:
3 $\sqrt{xyz}$ and 7 $\sqrt{xyz}$
$\sqrt[5]{x^2y}$ and 3 $\sqrt[5]{x^2y}$

Check the choices you have. The one that satisfies the above two conditions would be your correct choice

Hope this helps :)

7 0

3 years ago

Read 2 more answers

What does x=<br> What does x=

tiny-mole [99]

Answer:

12

Step-by-step explanation:

the angles of a triangle all add up to 180

thus, we can combine every term given and set them equal to 180 and solve for x

$9x + 72 = 180 \\ 180 - 72 = 108 \\ 108 \div 9 = 12$

4 0

3 years ago

Two chemicals A and B are combined to form a chemical C. The rate, or velocity, of the reaction is proportional to the product o

koban [17]

Answer: 17.6 grams

Step-by-step explanation:

As the problem tells us, the velocity of the reaction is proportional to the product of the quantities of A and B that have not reacted, so from this we get the next equation:

V = k[A][B]

where [A] represents the remaining amount of A, and [B] represents the remaining amount of B. To solve this equation we have to represent it through a differential equation, which is:

dx/dt = k[α - a(t)][β - b(t)] (1)

where,

k: velocity constant

a(t): quantity of A consumed in instant t

b(t): quantity of B consumed in instant t

α: initial quantity of A

β: initial quantity of B

Now we need to define the equations for a(t) and b(t), and for this we are going to use the law of conservation of mass by Lavoisier, with which we can say that the quantity of C in a certain instant is equal to the sum of the quantities of A and B that have reacted. Therefore, if we need M grams of A and N grams of B to form a quantity of M+N of C, then we can say that in a certain time, the consumed quantities of A and B are given by the following equations:

a(t) = ( M/M+N) · x(t)

b(t) = (N/M+N) · x(t)

where,

x(t): quantity of C in instant t

So for this problem we have that for 1 gram of B, 2 grams of A are used, therefore the previous equations can be represented as:

a(t) = (2/2+1) · x(t) = 2/3 x(t)

b(t) = (1/2+1) · x(t) = 1/3 x(t)

Now we proceed to resolve the differential equation (1) by substituting values:

dx/dt = k[α - a(t)][β - b(t)]

dx/dt = k[40 - 2x/3][50 - x/3]

dx/dt = k/9 [120 - 2x][150 - x]

We use the separation of variables method:

dx/[120-2x][150-x] = k/3 · dt

We integrate both sides of the equation:

∫dx/(120-2x)(150-x) = ∫kdt/9

∫dx/(15-x)(60-x) = kt/9 + c

Now, to integrate the left side of the equation we need to use the partial fraction decomposition:

∫[1/90(120-2x) - 1/180(150-x)] = kt/9 + c

1/180 ln(150-x/120-2x) = kt/9 + c

(150-x)/(120-2x) = Ce^{20kt}

Now we resolve by taking into account that x(0) = 0, and x(5) = 10,

for x(0) = 0 , (150-0)/(120-0) = Ce^{20k(0)} , C = 1.25

for x(5) = 10 , (150-10)/(120-(2·10)) = 1.25e^{20k(5)} , k ≈ 113 · 10^{-5}

Now that we have the values of C and k, we have this equation:

(150-x)/(120-2x) = 1.25e^{226·10^{-4}t}

and we have to clear by x, obtaining:

x(t) = 150 · (1 - e^{226·10^{-4}t} / 1 - 2.5e^{226·10^{-4}t})

Therefore the quantity of C that will be formed in 10 minutes is:

x(10) = 150 · (1 - e^{226·10^{-4}(10)} / 1 - 2.5e^{226·10^{-4}(10)})

x(10) ≈ 17.6 grams

8 0

3 years ago