Remark
If the two angles are complimentary they add up to 90°. So the first job is to find the third angle. In the diagram below, the third angle is labeled C, so you must find it first.
After that, you need to use the Pythagorean Theorem to solve for QC which at this point is not known.
After completing that, You need to find the cosine of P and Q so that they can be added together.
Step One
Find angle C
All triangles have 180°
P + Q are complementary. Given
P + Q = 90° Definition
P + Q + C = 180 Property of a triangle.
90 + C = 180 Subtract 90 from both sides.
C = 180 - 90
C = 90°
Step Two
Find QC
When you have a right triangle the Pythagorean Theorem can be used to find any missing side.
Sin(Q) = opposite / hypotenuse [See diagram]
Sin(Q) = 4/5 Given
a = 4
b = ??
c = 5
4^2 + b^2 = 5^2
16 + b^2 = 25 Subtract 16 from both sides.
b^2 = 25 - 16
b^2 = 9
Take the square root of both sides.
sqrt(b^2) = sqrt(9)
b = 3
Step 3
Define Cos(Q) and Cos(P)
Cos(Q) = adjacent side (3) over the hypotenuse (5)
Cos(Q) = 3/5
Cos(P) has the same basic definition. The adjacent side is 4 for angle P
Cos(P) = 4/5
Step Four
Add the two findings from Step 3
Cos(Q) + Cos(P) = 3/5 + 4/5 =
7/5 <<<<< Answer
Answer:
The answer should be 42
Step-by-step explanation:
One-third of 42 is 14 if you subtract 6 from 14, you should get 8.
The most important is to interpret (understand) the question.
You are asked to find the probability that the first roll is an even number and the second roll is not 2.
The joint probability is the product of both probabilities.
1) Probability that the first roll is even:
Three outcomes out of 6 are even: 3/6 = 1/2
2) Probability that the second roll is not 2.
Five outcomes out of 6 are no 2: 5/6
3) Joint probability = 1/2 * 5/6 = 5/12
Answer: 5/12
Answer:
C. 22,400.
Step-by-step explanation:
62.9% = 0.629 as a decimal fraction.
Total number of employees in small businesses in the county
= 270 * 132.
So the estimated number with less than $1000 savings
= 270 * 132 * 0.629
= 22,417.
Answer:
Step-by-step explanation:
I assume that the last question should read "cosE"