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Yuri [45]
2 years ago
8

From our lesson, what is your difficulty in dealing with exponential expressions?

Mathematics
1 answer:
aleksandrvk [35]2 years ago
3 0

Answer:

From the said lesson, the difficulty that I have been trough in dealing over the exponential expressions is the confusion that frequently occurs across my system whenever there's a thing that I haven't fully understand. It's not that I did not actually understand what the topic was, but it is just somewhat confusing and such. Also, upon working with exponential expressions — indeed, I have to remember the rules that pertain to dealing with exponents and frequently, I will just found myself unconsciously forgetting what those rule were — rules which is a big deal or a big thing in the said lesson because it is obviously necessary/needed over that matter. Surely, it is also a big help for me to deal with exponential expressions since it's so much necessary — it's so much necessary but I keep fogetting it.. hence, that's why I call it a difficulty. That's what my difficulty. And in order to overcome that difficulty, I will do my best to remember and understand well the said rules as soon as possible.

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Use the substitution method to determine the solution of the system of equations. y = -5x and 21x - 7y = 28
8_murik_8 [283]

Answer:

x = 1/2   y = -5/2

Step-by-step explanation:

Since we already know an equation for y, we just need to plug it into the other equation.

21x - 7(-5x) = 28

21x + 35x = 28

56x = 28

x = 1/2

Now that we know x, we substitute it into the other equation, to find y.

y = -5x

y = -5(1/2)

= -5/2

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3 years ago
Cut the circle into 7 pieces with just three straight cuts. Explain your reasoning
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How do i graph this
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Arianna correctly simplified an expression. When she substituted mc020-1. Jpg into the simplified expression, the value was â€"4
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Answer:

value was â€"4. Which could be Arianna’s original expression? One-sixth (negative 3 x minus 24) One-sixth (negative 5 x minus 8) One-sixth (negative 10 x minus 4) One-sixth (negative 12 x minus 16).

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A trapezoid was broken into two congruent triangles and a rectangle. A trapezoid is broken into 2 triangles and 1 rectangle. The
Naddika [18.5K]

complete question:

The picture below is the complete question.

Answer:

base of the triangles = 3 cm

Step-by-step explanation:

The trapezoid was broken into 2 congruent triangles and a rectangle. The 2 triangle have a height of 12 cm . The rectangle has a height of 12 cm and width of 14 cm .

The base length of the triangle can be computed as follows.

Note a congruent triangle have exactly the same three sides and exactly the same three angles.

area of a triangle = 1/2 × base × height

From the area of the trapezoid one can calculate the sides of the triangle.

area of the trapezoid = 1/2 × (a + b)h

where

a = top side

b = base side

h = height

area of the trapezoid = 1/2 × (a + b)h

area of the trapezoid = 1/2 × (14 + 20)12

area of the trapezoid = 1/2 × 34 × 12

area of the trapezoid = 34 × 6

area of the trapezoid = 204 cm²

204 = area of the triangles + area of the rectangle

204 =2 (1/2bh) + lw

where

b = base of triangle

h = height of triangle

l = length of rectangle

w = width of rectangle

204 = bh + (14 × 12)

204 = 12b + 168

12b = 204 - 168

12b = 36

divide both sides by 12

b = 36/12

b = 3 cm

base of the triangles = 3 cm

 

3 0
3 years ago
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