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3 years ago

How many times bigger is the interior angle of a nonogon than a exterior angle

1 answer:

4 0

Angles of a nonagon:

A nonagon consists of 9 angles. The sum of angles of a nonagon is 1260°.

A nonagon has 9 exterior angles. The sum of angles of the exterior angles of a nonagon is 360°.

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10 - 4 (3-2y) = 8y -5

Lisa [10]

Answer:

No Solutions

Step-by-step explanation:

10 - 4(3-2y) = 8y - 5

Distribute:

10 - 12 + 8y = 8y - 5

Simplify:

-2 + 8y = 8y - 5

Same to both sides

-2 + 5 = 8y - 8y

3 = 0y

No Solutions

Let me know if you have any questions

8 0

3 years ago

How much water should be added to 14mL of 15% alcohol solution to reduce the concentration to 7%

leonid [27]

You would need 12ml of water.

6 0

3 years ago

Whats half of 70.00 dollars

Liono4ka [1.6K]

Half of 70.00 dollars

To Find the HALF of something, Divide the number by 2

So 70.00 Dollars/ 2 Dollars

Answer is: 35 Dollars

To Check Answer Multiply the answer by 2

35 Dollars* 2= 70.00 Dollars.

6 0

3 years ago

Read 2 more answers

HELP ME PLEASE !!!!!!!!

lord [1]

Answer:

B and D

Step-by-step explanation:

A is false as it would be 3.08 when rounded.

C is false as it is rounded to the tenth not hundredth.

5 0

3 years ago

Read 2 more answers

An equation parallel and perpendicular to 4x+5y=19

UNO [17]

Answer:

Parallel line:

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

$y=\frac{5}{4}x-\frac{1}{2}$

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

$4x+5y=19$

we can change it into y=mx+b form

$5y=-4x+19$

$y=-\frac{4}{5}x+\frac{19}{5}$

so,

$m=-\frac{4}{5}$

Parallel line:

we know that slope of two parallel lines are always same

so,

$m'=-\frac{4}{5}$

Let's assume parallel line passes through (1,1)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-1=-\frac{4}{5}(x-1)$

now, we can solve for y

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

$m'=\frac{5}{4}$

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-2=\frac{5}{4}(x-2)$

now, we can solve for y

$y=\frac{5}{4}x-\frac{1}{2}$

4 0

3 years ago