here we have 3X to 5 seventh power in radical form
![3x^{5/7}](https://tex.z-dn.net/?f=%203x%5E%7B5%2F7%7D%20%20)
we need write this in radical form we knwo that ![x^{1/2} =\sqrt{x}](https://tex.z-dn.net/?f=%20x%5E%7B1%2F2%7D%20%3D%5Csqrt%7Bx%7D%20%20)
so ![3x^{5/7} =\sqrt[7]{3x^{5}}](https://tex.z-dn.net/?f=%203x%5E%7B5%2F7%7D%20%3D%5Csqrt%5B7%5D%7B3x%5E%7B5%7D%7D%20%20%20)
this will be the radical form .
Answer:
-25p
Step-by-step explanation:
Answer:
0.77 ounces
My apologies if my answer is wrong :)
Answer:
a) 1/2; reduction
b) 5/4; enlargement
Step-by-step explanation:
In each case, the scale factor is CP'/CP. When it is more than 1, the dilation is an enlargement.
Even before you run the numbers, you can tell if it is an enlargement or not. If the dilated figure is larger, P is closer to C than is P'. If P' is closer to C, then it is a reduction.
a) CP'/CP = (4-2)/4 = 2/4 = 1/2 . . . . a reduction
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b) CP'/CP = 25/20 = 5/4 . . . . an enlargement