What is the volume of a hemisphere with a radius of 39.4 ft, rounded to the nearest tenth of a cubic foot?
1 answer:
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let's recall that corresponding angles are equal, thus 105° twins, also let's recall that a flat-line has 180°.
since the two sides stemming from Ɣ are twins, the angles they make at the base are also twins, bearing in mind that a triangle has a sum of all interior angles of 180°.
Given:
side length = 6 ft
To find:
The area of the figure
Solution:
Area of the square = side × side
= 6 × 6
Area of the square = 36 ft²
Diameter of the semi-circle = 6 ft
Radius of the semi-circle = 6 ÷ 2 = 3 ft
Area of the semi-circle =
Area of the semi-circle = 14.13 ft²
Area of the figure = Area of the square - Area of the semi-circle
= 36 ft² - 14.13 ft²
= 21.87 ft²
Area of the figure = 21.9 ft²
The area of the figure is 21.9 ft².