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3 years ago

PLEASE HELP RIGHT NOW!!!!!!!!!

Mathematics

1 answer:

Anton [14]3 years ago

8 0

Answer:

SAS postulate

Step-by-step explanation:

The triangles have two congruent sides and one congruent angle. The congruent angle is the included angle. This meets SAS criteria.

<u>Hope this helps :-)</u>

<u>See also </u>brainly.com/question/18898343

<u>Image from </u><em>aplustopper</em>

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3. Suppose that you draw two cards from a standard 52 card deck. You replace the first card and shuffle thoroughly before you dr

Kruka [31]

Answer:

$\text{a)} \frac{1}{17} \text{b)} \frac{1}{221}\text{c)}\frac{12}{13}\text{d)}\frac{188}{221}$

Step-by-step explanation:

GIVEN: You draw two cards from a standard $52$ card deck. You replace the first card and shuffle thoroughly before you draw the second.

TO FIND: a) What is the probability that the first card is $7$ b) What is the probability that both cards are

SOLUTION:

Let $\text{A}$ and $\text{B}$ be two events such that

$\text{A}$ $=\text{first card drawn is 7}$

$\text{B}$ $=\text{Second card is 7}$

$\text{probability that first card is 7 =P(A)}$

<h3> $\text{P(A)}=\frac{\text{total 7 numbered cards}}{\text{total cards in deck}}$ </h3><h3> $\text{P(A)}=$ $\frac{4}{52}=\frac{1}{13}$ </h3>

$\text{probability that first card is 7 =P(A)}$

$\text{probability that both cards are 7}=$ $\text{first card is 7}\times\text{second card is 7}$

$\text{probability that both cards are 7}=$ $\text{P(A).P(B)}$

$\text{P(B)}=\frac{\text{total number of 7 numbered cards left}}{\text{total number of cards in deck left}}$

$\text{P(B)}=\frac{3}{51}=\frac{1}{17}$

$\text{probability that both cards are 7}=$ $\frac{1}{13}\times\frac{1}{17}$

$\text{probability that both cards are 7}=$ $\frac{1}{221}$

$\text{probability that first card is not 7}=1-\text{probability that first card is 7}$

$\text{probability that first card is not 7}=$ $1-\text{P(A)}$

$\text{probability that first card is not 7}=$ $1-\frac{1}{13}$

$\text{probability that first card is not 7}=$ $\frac{12}{13}$

$\text{probability that both cards are not 7}=$ $(\text{first card is not 7}).(\text{second card is not 7})$

$\text{probability that both cards are not 7}=$ $\text{[1-P(A)].[1-P(B)]}$

$\text{P(B)}=\frac{\text{total 7 numbered cards}}{\text{total cards left in deck}}$

$\text{probability that both cards are not 7}=$ $(1-\frac{1}{13})\times(1-\frac{4}{51})$

$\text{probability that both cards are not 7}=$ $\frac{12}{13}\times\frac{47}{51}$

8 0

3 years ago

Joes apple weights 4/5lbs. Marta weights 0.5 lbs. How much more does joes apple weight?<br>

Vlada [557]

Answer:

.3 lbs

Step-by-step explanation:

Convert Joe's apple weight into decimal form; 4/5=.8

.8lbs-.5lbs= .3lbs

3 0

3 years ago

Simplify 1.0-4<br> o<br> 1<br> y

Vilka [71]

Answer:

Theirs a app called photo math it does the math for you and you get a 100% correct answer

Step-by-step explanation:

4 0

3 years ago

How many solutions for x does the following equation have?

nikitadnepr [17]

Prolly wrong but I think B

5 0

3 years ago

Idk how to do this can you help me

slavikrds [6]

Equilateral triangle are also equiangular which means all angles are 60 degrees. thus our needed altitude is the leg of a right triangle with other leg 4 and hypotenuse 8. 4² +a² = 8²

a² = 48
a=√48 = 4√3

4 0

3 years ago