A parachutist's rate during a freefall reaches 126 miles per hour. What is this rate in feet per second? At this rate, how many
feet will the parachutist fall during 10 seconds of free-fall? In your computations, use the fact that 1 mile is equal to 5280 feet. Do not round your answers. 
2 answers:
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Answer:
Approximate length of the diagonal fencing needed is 45.25 cm.
Step-by-step explanation:
Here, each side of the square shaped land = 32 ft
Now, the diagonal fencing is made in side the plot so that the land is divided into two right triangles.
<u>In the triangle:</u>
Base side of the triangle = 32 cm
Perpendicular length of the triangle = 32 cm
Let us assume the hypotenuse of the triangle = k cm
⇒The length of the diagonal in the square = k cm
by <u>PYTHAGORAS THEOREM</u> in a right angled triangle:
⇒
or, k = 45.25 cm
Hence,the approximate length of the diagonal fencing needed to fence the square land is 45.25 cm.
Answer:
1:
2:
3:
Step-by-step explanation:
Question 1: When lines are parallel, that means they're slope is the same and there y-intercept is different. So the first step is to calculate the slope of BC. If you look at BC you'll notice it goes down by 2 and goes forward by 2 so the slope is -2/2 or -1. This completes one part of the slope-intercept form which is y=mx+b where m is the slope and b is the y-intercept. The y-intercept will be calculated using the point A. since the equation passes through point A
-1 = (-2)(-1) + b
-1 = 2 + b
-3 = b
y=-1x-3
Question 2: Same concept here, if you look at AC, you'll see it "rises" by 4 and "runs" by 5, thus the slope is 4/5. Since it passes through B we'll use that to find the y-intercept
5 = (4/5)(1) + b
5 = 4/5 + b
b = 4.2
Question 3: It "rises" by 6 and "runs" by 3, thus the slope is 6/3 which is 2.
Plug in known values
3=(3)(2) + b
3 = 6 + b
-3 = b