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myrzilka [38]
3 years ago
15

A parachutist's rate during a freefall reaches 126 miles per hour. What is this rate in feet per second? At this rate, how many

feet will the parachutist fall during 10 seconds of free-fall? In your computations, use the fact that 1 mile is equal to 5280 feet. Do not round your answers. ​

Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
5 0

Answer:

0.035

.35

Step-by-step explanation:

in one hour or in 3600 seconds the parachuterfalls 126 miles which means we have the following ratio

seconds:distance

3600:126

we want to find

1:x

To find x we divide 126 by 3600 (we do this because we divided 3600 by 3600 to get 1)

we get 0.035

This means that the parachuter falls at a rate of 0.035 ft/s

To find the distance fallen in 10 seconds we simply multiply 0.035 by 10

I do this and get .35

kogti [31]3 years ago
4 0

Answer:

this is to hard

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Solve for g(x) by replacing x with each domain value in the set. Solving for g(x) will give you these numbers:

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-13 is the only value that appears in the range set and in the multiple choice solutions. Therefore, the answer is C. -13

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3 years ago
Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p
kvv77 [185]

The question is an illustration of composite functions.

  • Functions c(n) and h(n) are \mathbf{c(n) = 5000 + 250n} and \mathbf{n(h) = 5h}
  • The composite function c(n(h)) is \mathbf{c(n(h)) = 5000 + 1250h}
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  • The interpretation is: <em>"the cost of working for 100 hours is $130000"</em>

The given parameters are:

  • $5000 in fixed costs plus an additional $250
  • 5 systems in one hour of production

<u>(a) Functions c(n) and n(h)</u>

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

\mathbf{c(n) = Fixed + Additional \times n}

This gives

\mathbf{c(n) = 5000 + 250 \times n}

\mathbf{c(n) = 5000 + 250n}

The function for number of systems is:

\mathbf{n(h) = 5 \times h}

\mathbf{n(h) = 5h}

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In (a), we have:

\mathbf{c(n) = 5000 + 250n}

\mathbf{n(h) = 5h}

Substitute n(h) for n in \mathbf{c(n) = 5000 + 250n}

\mathbf{c(n(h)) = 5000 + 250n(h)}

Substitute \mathbf{n(h) = 5h}

\mathbf{c(n(h)) = 5000 + 250 \times 5h}

\mathbf{c(n(h)) = 5000 + 1250h}

<u>(c) Find c(n(100))</u>

c(n(100)) means that h = 100.

So, we have:

\mathbf{c(n(100)) = 5000 + 1250 \times 100}

\mathbf{c(n(100)) = 5000 + 125000}

\mathbf{c(n(100)) = 130000}

<u>(d) Interpret (c)</u>

In (c), we have: \mathbf{c(n(100)) = 130000}

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

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Answer:

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