3 years ago

If x^(2) - 2 = 2^(2/3) + 2(-2/3) prove that x = 2^(1/3)+2^(-1/3)

Mathematics

1 answer:

dusya [7]3 years ago

6 0

Step-by-step explanation:

x² - 2 = 2^(2/3) + 2^(-2/3)

x² = 2^(2/3) + 2 + 2^(-2/3)

x² = (2^(1/3))² + 2 × 2^(1/3) × 2^(-1/3) +

(2^(-1/3))² (It is in the form of a²+2ab+b²)

x² = (2^(1/3) + 2^(-1/3))²

x = 2^(1/3) + 2^(-1/3)

You might be interested in

Given the equation square root of quantity 3x plus 6 end quantity equals 3, solve for x and identify if it is an extraneous solu

MissTica

Step-by-step explanation:

3x+6=3

-6 -6

3x =-3

÷3 ÷3

x= -1

4 0

3 years ago

OA. 29 feet OB. 19 feet OC. 6 feet OD. 36 feet

kipiarov [429]

What’s the question????

5 0

3 years ago

What is the solution to the equation -3d/a^2-2d-8 + 3/d-4 = -2/ d+2

Alex73 [517]

Answer:

d=1

Step-by-step explanation:

$\frac{-3d}{d^2-2d-8} +\frac{3}{d-4} =\frac{-2}{d+2}$

Lets factor the denominator d^2 -2d-8

d^2 - 2d - 8 = (d-4)(d+2)

$\frac{-3d}{(d-4)(d+2)} +\frac{3}{d-4} =\frac{-2}{d+2}$

Now make the denominators same

LCD: (d-4)(d+2)

$\frac{-3d}{(d-4)(d+2)} +\frac{3(d+2)}{(d-4)(d+2)} =\frac{-2(d-4)}{(d+2)(d-4)}$

Denominators are same on both sides

So equate the numerators

-3d +3(d+2) = -2(d-4)

-3d +3d +6 = -2d +8

6 = -2d + 8

subtract 8 on both sides

-2 = -2d

So d=1

3 0

2 years ago

Read 2 more answers

What are the answer for your these questions?

ozzi

Answer:

a. 11

b. 9

Step-by-step explanation:

A:

2 x 4 = 8

8 + 3 = 11

B:

-2 x -2 = 4

4 + 5 = 9

Hope this helps! Let me know if it was right!

5 0

3 years ago

Which of the following equations represents a quadratic relation?

iVinArrow [24]

Answer:

y=2x^2+1

Step-by-step explanation:

a quadratic equation has a x^2 term

4 0

2 years ago