Set up an algebraic equation: b=cost of ball
1.10=1+b+b
1.10=1+2b
subtract 1 from both sides
.10=2b
divide by 2 on both sides
ball=5 cents
Answer: <em><u>CAN YOU PLS MARK AS BRAINLIEST??</u></em>
a.x=11/4
b.x=6
c.x=21/2
d.x=0
Step-by-step explanation:
-2+3x+x=9-x
-2+3x+x=9
4x=9+2
4x=11
x=11/4
when you move a numerator to the other side it becomes a denominator
x+2=3/4x6
x+2=3/24
x=8-2
x=6
5-2x-12=14
2x=14-5+12
2x=21
x=21/2
1/2x=-3-1/2x+4-1
1/2x+1/2x=-3+4-1
x=0
Answer:
a. 0.7291
b. 0.9968
c. 0.7259
Step-by-step explanation:
a. np and n(1-p) can be calculated as:

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

#Define Y:
Y~(11.04,5.7408)

Hence, the probability of 12 or fewer is 0.8291
b. The probability that 5 or more fish were caught.
#Using normal approximation:

Hence, the probability of catching 5+ is 0.9968
c. The probability of between 5 and 12 is calculated as;
-From b above
and a ,
=0.7291

Hence, the probability of between 5 and 12 is 0.7259
Answer:
5610
Step-by-step explanation:
unaffected people will be (100%-2.5\%-50.75%)=46.75% of 12000:
