The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
<h3>How to determine the inverse relation?</h3>
The function is given as
f(x)=1/3x^2-3x+5
Start by rewriting the function in vertex form
f(x) = 1/3(x - 9/2)^2 -7/4
Rewrite the function as
y = 1/3(x - 9/2)^2 -7/4
Swap x and y
x = 1/3(y - 9/2)^2 -7/4
Add 7/4 to both sides
x + 7/4= 1/3(y - 9/2)^2
Multiply by 3
3x + 21/4= (y - 9/2)^2
Take the square roots
y - 9/2 = √(3x + 21/4)
This gives
y = 9/2 + √(3x + 21/4)
Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
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Answer:
B
Step-by-step explanation:
ITS B
35.625
How many times does 8 go into 285?
T=d/6+3
1. Fill in: t=12/6+3
2. Remember PEMDAS!! P(parenthesis)E(Exponents)M(multiply)D(divide)A(add)S(subtract)
So, you will divide 12 by 6 first, which equals out to 2.
3. Write your new equation: t=2+3
4. Add 2+3, which equals to 5.
t=5
The y-intercepts are points where the graph of a function or an equation crosses or “touches” the y-axis of the Cartesian Plane.
