All categories

3 years ago

What is the grates common factor of 16 and 48

Mathematics

2 answers:

Jobisdone [24]3 years ago

5 0

The GCF of 16 and 48 is 16.

lisabon 2012 [21]3 years ago

4 0

The gcf of 16 and 48 is the largest positive integer that divides the numbers 16 and 48 without a remainder<span>. Spelled out, it is the greatest common factor of 16 and 48 Is what google says.</span>

You might be interested in

victor want to make a book tower of height 48 cm .If the thickness of book is 12 mm ,how many books will he need to make the des

lions [1.4K]

Answer:

Step-by-step explanation:

1. Change 48 cm to mm, which will give you 480 mm

2. Divide 480 mm by 12 mm, that will give you 40

Therefore, Victor needs 40 books to make his desired height.

6 0

2 years ago

Determine the exact solution to the following in radians.

Sloan [31]

3sinx+1=sinx
2sinx+1=0
2sinx=-1
sinx=-1/2
x=sin^-1 (1/2) = 30 = $\pi$ /6 (when finding the inverse, always take the positive value, ignore the negative sign)
x is therefore negative in 3rd and 4th quadrant
Therefore values of x are:
180+30=210 = 7 $\pi$ /6
360-3=330 = 11 $\pi$ /6

3 0

3 years ago

EXPAND:

Sladkaya [172]

Answer:

$\displaystyle A) 5\log( {x}^{} ) + 2 \log( {y}^{} )$

Step-by-step explanation:

we would like to expand the following logarithmic expression:

$\displaystyle \log( {x}^{5} {y}^{2} )$

remember the multiplication logarithmic indentity given by:

$\displaystyle \rm \log( \alpha \times \beta ) \iff \log( \alpha ) + \log( \beta )$

so our given expression should be

$\displaystyle \log( {x}^{5} ) + \log( {y}^{2} )$

by exponent logarithmic property we acquire:

$\displaystyle 5\log( {x}^{} ) + 2 \log( {y}^{} )$

hence, our answer is A

5 0

3 years ago

What is the area of a circle. Using 3.14 for. A circle with diameter of 8.4 ft.

ira [324]

Hey there! I'm happy to help!

First, let's find the radius. The radius is half of the diameter.

8.4/2=4.2

Here's how to find the area of a circle.

Square the radius.

4.2²=17.64

And multiply by pi (3.14 in our case)

17.64(3.14)=55.3896

We round to the nearest tenth, giving us an area of 55.4 ft²

Have a wonderful day! :D

5 0

3 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

4 0

3 years ago

Read 2 more answers