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3 years ago

5

John wants to fence in a portion of his backyard. ... How many feet of fencing does john need to buy to enclose this area? ... H

ow many square yards of carpet will she need to complete the room?

1 answer:

Lelechka [254]3 years ago

3 0

For this problem you need to find the area.
To find area, you multiply the width by the length.
You multiply 12 1/2 by 5 1/2 and you get 31 1/4
This is how you do it::

= 25/2 × 5/2

= (25 × 5) / (2 × 2)

= 125/4

= 125/4

<span>= 31 1/4

So you know that the area is 31 1/4 yards.
In the question it asks HOW MANY FEET so we have to convert 31 1/4 yards to feet.
1 yard= 3 feet
31 1/4 *3= </span><span>93.75
<span>John need to buy 93.75 feet of fencing to enclose the area.</span></span>

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Multiply 6/5 by the reciprocal of (-3/8)

weeeeeb [17]

Answer:

-48/15, simplified to -16/5

Step-by-step explanation:

The reciprocal of -3/8 is -8/3. So the equation will be 6/5 x -8/3. Multiply numerators then multiply denominators to get -48/15. This can simplify to -16/5 by dividing both by 3.

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3 years ago

Read 2 more answers

What is the product of − 3/11 and − 2/15? please explain.

emmainna [20.7K]

ANSWER

The product is

$\frac{2}{55}$

EXPLANATION

To find the product of

$- \frac{3}{11}$

and

$\frac{ - 2}{15}$

means we should multiply the two fractions.

We multiply to obtain,

$- \frac{3}{11} \times - \frac{2}{15}$

$= - \frac{3}{11} \times - \frac{2}{3 \times 5}$

Cancel the common factors:

$= - \frac{1}{11} \times - \frac{2}{5}$

Now, multiply the numerators separately and the denominators too separately.

$= \frac{ - 1 \times - 2}{11 \times 5}$

This simplifies to,

$= \frac{2}{55}$

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3 years ago

What is m to the power of 2 minus 11m minus 60 in product/sum method

Nana76 [90]

m^2 -11m -60 = 0

m^2 -11m =60

(m^2 -11m + 121/4) = 361/4

(m - 11/2)^2 = 361/4

m - 11/2 = + or - 19/2

m = 11/2 + 19/2, 11/2 - 19/2

m = 15, -4

---------------------------------------------------

m^2 -11m -60

(11 +- Square root (121 +240))/2

11/2 +- 19/2

m= 15, -4

----------------------------------------------------

m^2 -11m -60

(m - 15) (m + 4)

m = 15, -4

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4 years ago

Pls is easy but idk how to do it :/

ludmilkaskok [199]

Answer:check the pic

Step-by-step explanation:

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4 years ago

Read 2 more answers

Line Segment BC has endpoints B (3,5) and C (7,15). Find the missing coordinates of A (x,9) and D (17,y) such that AB and CD are

o-na [289]

Answer:

<em>x=-7</em>

<em>y=11</em>

Step-by-step explanation:

<u>Perpendicular Vectors</u>

Two vectors defined as their endpoints $\vec u=$ and $\vec v=$ are perpendicular if their dot product a.b is zero. The dot product is

$\vec u.\vec v=ac+bd$

In other words

ac+bd=0

Let's treat all the points as the extremes of vectors, so we can easily find the missing coordinates

B (3,5) and C (7,15) define a segment, the vector

$\overrightarrow{BC}==$

The point A is A (x,9), we need to form a vector with B

$\overrightarrow{AB}==$

this vector must be perpendicular to BC, so, applying the dot product we have

$4(x-3)+40=0$

$4x-12=-40$

$x=-7$

The point D is D(17,y), we need to form a vector with C

$\overrightarrow{CD}==$

this vector must be perpendicular to BC, so, applying the dot product we have

$(4)(10)+(10)(y-15)=0$

$40+10y-150=0$

$10y=110$

$y=11$

The points are

$\boxed{A(-7,9), D(17,11)}$

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3 years ago