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Verdich [7]
2 years ago
14

30/50 of earth atomospere is made up nitrogen while only 21/100 is made up of oxygen what fraction of earth atmosphere is either

nitrogen or oxygen
Mathematics
1 answer:
lara31 [8.8K]2 years ago
3 0

Answer:

81/100 of the atmosphere consists of those two elements

Step-by-step explanation:

3/5+21/100  >  81/100

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How can you simplify integer expressions that contain more than one operation.
Nikitich [7]

Answer:

I would say use pemdas

Step-by-step explanation:

Parenthesis

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8 0
2 years ago
Gasoline is sold by the gallon. If 5 gal costs $17.35, how much would 12 gal cost?
Illusion [34]

Answer: $41.64

Step-by-step explanation: $17.37/5=3.47, so 3.47 x 12 = $41.64

8 0
3 years ago
Someone help me pleaseeeeeeeee
Komok [63]

Answer:

The first option (0.80)

Step-by-step explanation:

First, we need to find all the outcomes which meet the criteria, and in this case there are 1,3,5,6,7,8,9,10. In total we have 8 outcomes that meet our criteria out of 10 outcomes,, therefore the probability of the outcome to be greater than 4 or an odd number equals...

8 / 10 = 0.8

7 0
2 years ago
Determine the Perimeter of the shape #1.
Hatshy [7]

Answer:

56.8

Step-by-step explanation:

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6 0
3 years ago
Plz help in solving these 2 questions with steps and explanation!!
fomenos

Answer:

\large\boxed{Q1:\ x=2\ or\ x=5}\\\boxed{Q2:\ x=1-\sqrt{21}\ or\ x=1+\sqrt{21}}

Step-by-step explanation:

\text{Use the quadratic formula:}\\\\ax^2+bx+c=0\\\\\text{If}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\==========================================

\bold{Q1}\\\\x^2-7x+10=0\\\\a=1,\ b=-7,\ c=10\\\\b^2-4ac=(-7)^2-4(1)(10)=49-40=9>0\\\\\sqrt{b^2-4ac}=\sqrt9=3\\\\x_1=\dfrac{-(-7)-3}{2(1)}=\dfrac{7-3}{2}=\dfrac{4}{2}=2\\\\x_2=\dfrac{-(-7)+3}{2(1)}=\dfrac{7+3}{2}=\dfrac{10}{2}=5\\\\========================================

\bold{Q2}\\x^2-2x=20\qquad\text{subtract 20 from both sides}\\\\x^2-2x-20=0\\\\a=1,\ b=-2,\ c=-20\\\\b^2-4ac=(-2)^2-4(1)(-20)=4+80=84>0\\\\\sqrt{b^2-4ac}=\sqrt{84}=\sqrt{4\cdot21}=\sqrt4\cdot\sqrt{21}=2\sqrt{21}\\\\x_1=\dfrac{-(-2)-2\sqrt{21}}{2(1)}=\dfrac{2-2\sqrt{21}}{2}=1-\sqrt{21}\\\\x_2=\dfrac{-(-2)+2\sqrt{21}}{2(1)}=\dfrac{2+2\sqrt{21}}{2}=1+\sqrt{21}

3 0
3 years ago
Read 2 more answers
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