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Schach [20]
3 years ago
14

What is -4/8 reduced

Mathematics
2 answers:
kumpel [21]3 years ago
6 0

If you mean simplifying -4/8 simplified is -2/4 or -1/2 which in decimal form is   -0.5 so it is technically a negative half.

Reika [66]3 years ago
6 0

-4/8 = -2/4 = -1/2

-1/2

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[(b+3)÷(a–2)](−4) if a=−5, b=6
MAXImum [283]

Answer:

36/7

Step-by-step explanation:

{(6+3)/(-5-2)}(-4)

36/7

4 0
3 years ago
Help now now now!!!!!!!!!!!!!!
WARRIOR [948]
The answer is 2. Here's why:

First if all, anything to the power of 0 is 1.
So n^0=1.
You need to plug in 3 for m, so then 6(3)^-1.
3^-1=1/3.
6 × 1/3= 6/3=2
2×1=2.
3 0
3 years ago
Read 2 more answers
Can somebody help please real quick
mylen [45]

I think it's the 2nd option.

8 0
3 years ago
Read 2 more answers
On a test that has a normal distribution, a score of 19 falls one standard deviation below the mean, and a score of 40 falls two
nexus9112 [7]

Hi there!

We can use the following equation:

\large\boxed{z = \frac{x-\mu}{\sigma}}

z = amount of standard deviations away a value is from the mean (z-score)

σ = standard deviation

x = value

μ = mean

Plug in the knowns for both and rearrange to solve for the mean:

-1 = \frac{19-\mu}{\sigma}\\\\-\sigma = 19 - \mu\\\\ \sigma = -19 + \mu

Other given:

2 = \frac{40-\mu}{\sigma}\\\\2\sigma = 40- \mu\\\\ \sigma = 20 - \frac{\mu}{2}

Set both equal to each other and solve:

-19 + \mu = 20 - \frac{\mu}{2}\\\\\frac{3\mu}{2} = 39 \\\\3\mu = 78 \\\\\boxed{\mu = 26 }

5 0
2 years ago
Any1 can help me wif q12
xenn [34]
I) HCF - use the smallest powers of each common factors
HCF (A,B) = 2^2 × 3^4 × 5^2

LCM - use the highest powers of each factors
LCM (A,B) = 2^4 × 3^6 × 5^2 × 7^2 × 11^16

ii) Add powers together.
A×B = 2^6 × 3^10 × 5^4 × 7^2 × 11^16
sqrt(A × B)
Divide powers by 2.
sqrt(A × B) = 2^3 × 3^5 × 5^2 × 7 × 11^8

iii) C = 3^7 × 5^2 × 7
Ck = (3^7 × 5^2 × 7) × k
B/c Ck should be a product that is a perfect cube, the powers of the products should be divisible by 3.
(3^7 × 5^2 × 7) × k = 3^9 × 5^3 × 7^3

k = (3^9 × 5^3 × 7^3) / (3^7 × 5^2 × 7)
k = 3^(9-7) × 5^(3-2) × 7^(3-1)
k = 3^2 × 5 × 7^2
8 0
3 years ago
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